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timurjin [86]
2 years ago
7

Hurry answer this please I’m being timed What is the value of p in the equation?

Mathematics
1 answer:
melisa1 [442]2 years ago
7 0

Answer:

it will be 0

Step-by-step explanation:

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I will mark brainliest
BARSIC [14]

Answer:

Your answer would be D, the last one

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2 years ago
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Simplify this please​
Fittoniya [83]

Answer:

<h2><em><u>4</u></em></h2>

Step-by-step explanation:

\sqrt[3]{64}

=  \sqrt[3]{4 \times 4 \times 4}

= <em><u>4</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

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2 years ago
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Pam has taken 4 tests. She scored an 82, 94, 89 and 92. What would she need to score on her 5th test to have a mean of 90?
zavuch27 [327]

Answer:

93

Step-by-step explanation:

5*90 = 450

82+94+89+92 = 357

so

450-357 = 93

hope this helped :)

5 0
3 years ago
The price of a $250 item after successive discounts of 20% and<br> 30% is?
Ivan

Answer:

The price of item after successive discounts are 20% and 30% is $140.

Step-by-step explanation:

The marked price of item is $250.

Two successive discounts are 20% and 30%.

Price of item after discounts of 20% is

250-\frac{20}{100}(250)=250-50=200

New price of item after first discount is $200.

Price of item after second discount, i.e., 30% is

200-\frac{30}{100}(200)=200-60=140

Therefore, the price of item after successive discounts are 20% and 30% is $140.

3 0
3 years ago
An automobile manufacturer claims that its car has a 35.935.9 miles/gallon (MPG) rating. An independent testing firm has been co
Serjik [45]
<h2>Answer with explanation:</h2>

Let \mu be the population mean.

For the given claim , we have

Null hypothesis : H_0: \mu=35.9

Alternative hypothesis :  H_a: \mu\neq35.9

Since alternative hypothesis is two-tailed , so the test is a two-tailed test.

Given : Sample size : n=220  ;

Sample mean: \overline{x}=35.6  ;

Standard deviation: s=2.2

Test statistic for population mean:

z=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

z=\dfrac{35.6-35.9}{\dfrac{2.2}{\sqrt{220}}}\approx-2.02

By using the standard normal distribution table of z , we have

P-value ( two tailed test ) : 2P(Z>|z|)=2(1-P(Z

=2(1-P(z

Since , the P-value is greater than the significance level of \alpha=0.02 , it means we do not have sufficient evidence to reject the null hypothesis.

5 0
3 years ago
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