Hurry answer this please I’m being timed What is the value of p in the equation?

$36\%$ of the beans in Pythagoras's soup are lentils, and $33\frac13\%$ of those lentils are green. If Pythagoras removes all th

bulgar [2K]

Question is not proper, Proper question is given below;

36% of the beans in Pythagoras's soup are lentils, and 33 1/3% of those lentils are green.

If Pythagoras removes all green lentils from his soup, then x% of the original beans remain. What is x?

Answer:

88% of the original beans remains $(x)$ after removing green lentils.

Step-by-step explanation:

Given:

Let the Original beans be 'n'.

Now given:

36% of the beans in Pythagoras's soup are lentils.

So we can say that;

Amount of lentils = $\frac{36}{100}n=0.36n$

Also Given:

33 1/3% of those lentils are green

Amount of green lentils = $33\frac{1}{3}\%\ \ Or \ \ \frac{100}{3}\%$

Amount of green lentils = $\frac{100}{3}\times 0.36n\times\frac{1}{100}= 0.12n$

Now we need find the percentage of original beans remain after removing green lentils.

Solution:

percentage of original beans remain ⇒ $x\%$

To percentage of original beans remain after removing green lentils we will subtract Amount of green lentils from Original beans and then multiplied by 100.

framing in equation form we get;

$x\%$ = $(n-0.12n)\times 100=88n \ \ \ Or \ \ \ 88\%$

Hence 88% of the original beans remains $(x)$ after removing green lentils.

8 0

3 years ago

How do I solve 1/2 in minus 3 equals 5

Mandarinka [93]

Answer:

n = 16

Step-by-step explanation:

$\dfrac{1}{2}n-3=5\\\\\dfrac{1}{2}n=8 \qquad\text{add 3}\\\\n=16 \qquad\text{multiply by 2}$

___

In general, you identify the terms containing the variable. Then figure out what is being done to the variable. Here, it is multiplied by 1/2 and then 3 is subtracted. You undo these operations in reverse order.

Undo the subtraction of 3 by adding 3. Undo the multiplication by 1/2 by multiplying by its inverse, 2. Of course, the rules of equality tell you that anything you do to one side of the equation must also be done to the other side.

You can consider it as "unwrapping the package". You start at the outside, the last operation applied, and work your way in.

4 0

3 years ago

In 5 years, Dad will be three times as old as his daughter Jill will be then. If the sum of their present ages is 50, how old ar

grandymaker [24]

First, we know (D is dad, J is Jill) that D+J=50.
Second, in 5 years D will be 3 times as old so
(D+5)= 3*(J+5)
Moving on, if we know D+J=50 then D=(50-J) is true.Taking that relationship and substituting for D in the other equation, it becomes
50 - J + 5 = 3 * (J + 5)
Then, it becomes 50 - J + 5 = (3 * J) + (3 * 5)
Then, 55 - J = (3 * J) + 15
Then, 55 - 15 = (3 * J) + J
which becomes 40 = 4*J

6 0

3 years ago

Read 2 more answers

AB and BA name the same ray. Always Never Sometimes

Hitman42 [59]

They are never the same ray. ray AB begins at point A and goes through point B to infinity and ray BA begins at point B and goes through point B to infinity

5 0

3 years ago

Read 2 more answers

Find the product of (a-2b)(a-b)

Oliga [24]

Answer:

a^2-3ab+2b^2

Step-by-step explanation:

(a-2b)(a-b)

a^2-2ab-ab+2b^2

a^2-3ab+2b^2

8 0

4 years ago