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Kryger [21]
3 years ago
5

46.6% Oxygen (O)

Biology
1 answer:
goldenfox [79]3 years ago
3 0
A im guessing? soz if i get it wrong.
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In corn, red kernel color (R) is dominant to yellow (r) and smooth kernel texture (W) is dominant to wrinkled (w).
Wewaii [24]

Answer:

a. df =  3, chi-square = 1.7333, p value = 7.815

b. we fail to reject null hypothesis

c. it is independent of kernel texture

Explanation:

h0; there is independence

h1; no independence

9:3:3:1 this is the phenotypic ratio

9+3+3+1 = 16

330 red smooth  + 97 red wrinkled  + 101 yellow smooth  + 32 yellow wrinkled

total observed = 560

1. the degree of freedom = n-1

n =4, 4-1 = 3

to get the chi square computation

(O-E)²/E

expected value for red smooth,

9/16 x 560 = 315

chisquare = (330-315)²/315 = 0.7143

expected for red wrinkled

3/16*560 = 105

chisquare = (97-105)²/105 = 0.6095

expected for yellow smooth

3/16*560 = 105

chisquare = (101-105)²/105 = 0.1524

expected for yelow wrinkled

1/16 * 560 = 35

chisquare = (32-35)²/35 = 0.2571

total chisquare = 0.7143+0.6095+0.1524+0.2571

= 1.7333

with probability = 0.05, df = 3, the value of the chi square from x² table = 7.815

1.7333 < 7.815

so  we fail to reject the null

c. we conclude that kernel color is independent of kernel texture

7 0
2 years ago
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