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Fynjy0 [20]
3 years ago
8

If 75% is £45 what is the full cost?

Mathematics
1 answer:
dimulka [17.4K]3 years ago
6 0
ANSWER: 60

75/100 = 3/4

45 divided by 3 is 15
15 multiplied by 4 is 50 (=4/4 = 100%)
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Do Audience Ratings Differ Based on the Genre of the Movie? The dataset HollywoodMovies includes a quantitative variable on the
Juli2301 [7.4K]

Answer:

Step-by-step explanation:

Hello!

(a) Which genre has the highest mean audience score? The lowest mean audience score?

1) Action \frac{}{X}_1= 58.63

2) Comedy \frac{}{X}_2= 59.11

3) Drama \frac{}{X} _3 = 72.10

4) Horror \frac{}{X}_4= 48.65

The lowest mean score is  \frac{}{X}_4= 48.65

The highest mean score is  \frac{}{X} _3 = 72.10

(b) Which genre has the highest median score? The lowest median score?

1) Action Me₁= 51.00

2) Comedy Me₂= 58.00

3) Drama Me₃= 72.00

4) Horror Me₄= 52.00

The Lowest median is Me₁= 51.00

The Highest median is Me₃= 72.00

(c) In which genre is the lowest score, and what is that score? In which genre is the highest score, and what is that score?

Lowest or minimum scores:

1) Action 32.00

2) Comedy 31.00

3) Drama 46.00

4) Horror 25.00

The genre with the lowest score is "Comedy"

Highest or maximum scores:

1) Action 93.00

2) Comedy 93.00

3) Drama 91.00

4) Horror 78.00

There are two genres with the highest score "Action" and "Comedy"

(d) Which genre has the largest number of movies in that category?

The number of movies for each category corresponds to the sample sizes:

1) Action n₁= 32

2) Comedy n₂= 27

3) Drama n₃= 21

4) Horror n₄= 17

The largest number of movies sampled was for the genre "Action"

(e) Calculate the difference in mean score between comedies and horror movies, and give notation with your answer, using i, for the mean comedy score and, for the mean horror score.

Comedy \frac{}{X}_C= 59.11

Horror \frac{}{X}_H= 48.65

\frac{}{X}_C -  \frac{}{X}_H= 59.11 - 48.65= 10.46

I hope this helps!

5 0
3 years ago
Use the given transformation to evaluate the integral. double integral 9xy dA R , where R is the region in the first quadrant bo
lianna [129]

It looks like the boundaries of R are the lines y=\dfrac23x and y=3x, as well as the hyperbolas xy=\frac23 and xy=3. Naturally, the domain of integration is the set

R = \left\{(x,y) ~:~ \dfrac{2x}3 \le y \le 3x \text{ and } \dfrac23 \le xy \le 3 \right\}

By substituting x=\frac uv and y=v, so xy=u, we have

\dfrac23 \le xy \le 3 \implies \dfrac23 \le u \le 3

and

\dfrac{2x}3 \le y \le 3x \implies \dfrac{2u}{3v} \le v \le \dfrac{3u}v \implies \dfrac{2u}3 \le v^2 \le 3u \implies \sqrt{\dfrac{2u}3} \le v \le \sqrt{3u}

so that

R = \left\{(u,v) ~:~ \dfrac23 \le u \le 3 \text{ and } \sqrt{\dfrac{2u}3 \le v \le \sqrt{3u}\right\}

Compute the Jacobian for this transformation and its determinant.

J = \begin{bmatrix}x_u & x_v \\ y_u & y_v\end{bmatrix} = \begin{bmatrix}\dfrac1v & -\dfrac u{v^2} \\\\ 0 & 1 \end{bmatrix} \implies \det(J) = \dfrac1v

Then the area element under this change of variables is

dA = dx\,dy = \dfrac{du\,dv}v

and the integral transforms to

\displaystyle \iint_R 9xy \, dA = \int_{2/3}^3 \int_{\sqrt{2u/3}}^{\sqrt{3u}} \frac{dv\,du}v

Now compute it.

\displaystyle \iint_R 9xy \, dA = \int_{2/3}^3 \ln|v|\bigg|_{v=\sqrt{2u/3}}^{v=\sqrt{3u}} \,du \\\\ ~~~~~~~~ = \int_{2/3}^3 \ln\left(\sqrt{3u}\right) - \ln\left(\sqrt{\frac{2u}3}\right) \, du \\\\ ~~~~~~~~ = \frac12 \int_{2/3}^3 \ln(3u) - \ln\left(\frac{2u}3\right) \, du \\\\ ~~~~~~~~ = \frac12 \int_{2/3}^3 \ln\left(\frac{3u}{\frac{2u}3}\right) \, du \\\\ ~~~~~~~~ = \frac12 \ln\left(\frac92\right) \int_{2/3}^3 du \\\\ ~~~~~~~~ = \frac12 \ln\left(\frac92\right) \left(3-\frac23\right) = \boxed{\frac76 \ln\left(\frac92\right)}

7 0
2 years ago
Write the second factor in the equation as a product of 10s
ki77a [65]

Answer:

1 and 10 2 and 5

Step-by-step explanation:

1*10=10

2*5=10

1+1+1+1+1+1+1+1+1+1=10

2+2+2+2+2=10

5+5=10

3 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=4%28x%20-%201%29%20%7B%7D%5E%7B2%7D%20%20-%209" id="TexFormula1" title="4(x - 1) {}^{2} - 9"
Aloiza [94]

Step-by-step explanation:

(a-b)^2=(a^2-2*a*b+b^2)

4*(x^2-2x+1)-9=4x^2-8x+4-9=4x^2-8x-5

if you have to calculate the Δ

there is it: 4x^2-8x-5=0

Δ=b^2-4*a*c=64-4*4*(-5)=64+80=144

x_{1,2}=-b±Δ/2*a=8±12/8=

x_{1}=8+12/8=20/8|:4=5/2

x_{2}=8-12/8=-4/8|:4=-1/2

4 0
3 years ago
Mrs. Prescott baked 24 cookies. 5 sixths of the cookies were oatmeal. How many oatmeal cookies did Mrs. Prescott bake?
zlopas [31]
Mrs Prescott baked 24 cookies
24/6=4  4 represents 1 sixth
5 sixths are oatmeal, 5x4=20
20 cookies are oatmeal cookies
 <span />
6 0
3 years ago
Read 2 more answers
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