Answer:
is not possible
Step-by-step explanation:
<u><em>The question in English is</em></u>
we are building a road that links the points a = (12 ,21) and b =(17,23) another point is in c =(3,9) it is possible that a single road allows to join these three points?
we know that
The formula to calculate the slope between two points is equal to

step 1
Find the slope ab
we have
a = (12 ,21) and b =(17,23)
substitute


step 2
Find the slope ac
we have
a = (12 ,21) and c =(3,9)
substitute


simplify

step 3
Compare slopes ab and ac
The slopes are different
That means ----> is not possible that a single road allows to join these three points
Answer:
a lot of different answers
Step-by-step explanation:
Read this sentence in the problem carefully.
"<span>The number of pages in each program is determined by the number of graduates."
That means that you can have any number of graduates, and you will figure out the number of pages in the program depending on the number of graduates.
g, the number of graduates, is the independent independent variable.
p, the number of pages, is the dependent variable.
</span>
Answer: 0.11
Step-by-step explanation: (2/3) / 6 = 0.11
Answer:
d = k·sin(2θ)·sin(α)/(sin(θ)·sin(β))
Step-by-step explanation:
The Law of Sines tells us that sides of a triangle are proportional to the sine of the opposite angle. This can be used along with a trig identity to demonstrate the required relation.
__
<h3>top triangle</h3>
The law of sines applied to the top triangle is ...
BC/sin(A) = AC/sin(θ)
Triangle ABC is isosceles, so the base angles at B and C are congruent. Then the angle at vertex A is ...
∠A = 180° -θ -θ = 180° -2θ
A trig identity tells us the sine of an angle is equal to the sine of its supplement. That means the sine of angle A is ...
sin(A) = sin(180° -2θ) = sin(2θ)
and our above Law of Sines equation tells us ...
BC = sin(A)/sin(θ)·AC = k·sin(2θ)/sin(θ)
__
<h3>bottom triangle</h3>
The law of sines applied to the bottom triangle is ...
DC/sin(B) = BC/sin(D)
d/sin(α) = BC/sin(β)
Multiplying by sin(α) we have ...
d = BC·sin(α)/sin(β)
__
Using our expression for BC gives the desired relation:
d = k·sin(2θ)·sin(α)/(sin(θ)·sin(β))