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defon
3 years ago
9

Solve the inequality X+ 7 < 4x+ 25 The solution is x​

Mathematics
1 answer:
Mazyrski [523]3 years ago
8 0

Answer:

x > -6

Step-by-step explanation:

Solve the following inequality:

x + 7 < 4x + 25

-Take 4x and subtract it from x :

x - 4x  + 7 < 4x - 4x + 25

-3x + 7 < 25

-Subtract 7 on both sides:

-3x + 7 - 7< 25 - 7

-3x < 18

-When you are dividing an integer by a negative integer, then the inequality sign changes. So, Take -3x and divide it on both sides:

\frac{-3x}{-3} < \frac{18}{-3}

x > -6

Therefore, the answer is x > -6.

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For every 1/4 mi Pascal walks Lucien runs 2/3 mi. How many miles does Pascal walk for every 1 mi Lucien runs? Write your answers
attashe74 [19]

Answer:

Step-by-step explanation:  The answer is 0.5

7 0
4 years ago
All points on a given line have their y-coordinate as 9. What is the equation of this line? A. x + y = 9 B. x – y = 9 C. x = 9 D
Phoenix [80]

D. y = 9 because it has a complete zero slope while the y-intercept of the equation is 9, so the equation is y = 9.

4 0
3 years ago
Read 2 more answers
Hey so im also looking for the first answer and the choices were “ is not “ and “ is “
dexar [7]

so the investigator found the skid marks were 75 feet long hmmm what speed will that be?

s=\sqrt{30fd}~~ \begin{cases} f=\stackrel{friction}{factor}\\ d=\stackrel{skid}{feet}\\[-0.5em] \hrulefill\\ f=\stackrel{dry~day}{0.7}\\ d=75 \end{cases}\implies s=\sqrt{30(0.7)(75)}\implies s\approx 39.69~\frac{m}{h}

nope, the analysis shows that Charlie was going faster than 35 m/h.

now, assuming Charlie was indeed going at 35 m/h, then his skid marks would have been

s=\sqrt{30fd}~~ \begin{cases} f=\stackrel{friction}{factor}\\ d=\stackrel{skid}{feet}\\[-0.5em] \hrulefill\\ f=\stackrel{dry~day}{0.7}\\ s=35 \end{cases}\implies 35=\sqrt{30(0.7)d} \\\\\\ 35^2=30(0.7)d\implies \cfrac{35^2}{30(0.7)}=d\implies 58~ft\approx d

4 0
3 years ago
Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o
kirza4 [7]

Answer:

a) H0: \sigma = 1.34

H1: \sigma \neq 1.34

b) df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

c) t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

\sigma_o =1.34 the value that we want to test

p_v represent the p value for the test

t represent the statistic  (chi square test)

\alpha=0.01 significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: \sigma = 1.34

H1: \sigma \neq 1.34

The statistic is given by:

t=(n-1) [\frac{s}{\sigma_o}]^2

Part b

The degrees of freedom are given by:

df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

Part c

Replacing the info we got:

t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0
3 years ago
Tionna has saved dimes and quarters in her piggy bank. Define the variables
olya-2409 [2.1K]

Step-by-step explanation:

y = .10d + .25q

y is the total amount, if you have d dimes and q quarters

4 0
3 years ago
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