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3 years ago

Is it true lines have endpoints?

Mathematics

2 answers:

kakasveta [241]3 years ago

6 0

No, lines continue for infinity. Line segments have end points.

blondinia [14]3 years ago

6 0

Lines do not have endpoints.

They extend forever in both directions.

So this is a false statement.

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If f(x) = 3x - 1 and g(x) = x + 2, find (f + g)(x).

Alexxx [7]

Answer:

4x + 1

Step-by-step explanation:

Multiply f + g by x because f + g is in parenthesis:

f(x) + g(x)

Then implement equation #1 for f(x) into our equation:

3x - 1 + g(x)

Then implement the other equation for g(x) into our equation:

3x - 1 + x + 2

Then switch the positions of -1 and +x:

3x + x - 1 + 2

Simmplify:

4x + 1

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3 years ago

83/10y-(38/11-11/4y)

IrinaK [193]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Please help!!!!!!!!!

kotykmax [81]

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3 years ago

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Determine whether the improper integral converges or diverges, and find the value of each that converges.

Ksju [112]

Answer:converge at $I=\frac{1}{3}$

Step-by-step explanation:

Given

Improper Integral I is given as

$I=\int^{\infty}_{3}\frac{1}{x^2}dx$

integration of $\frac{1}{x^2}$ is - $\frac{1}{x}$

$I=\left [ -\frac{1}{x}\right ]^{\infty}_3$

substituting value

$I=-\left [ \frac{1}{\infty }-\frac{1}{3}\right ]$

$I=-\left [ 0-\frac{1}{3}\right ]$

$I=\frac{1}{3}$

so the value of integral converges at $\frac{1}{3}$

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4 years ago