Answer:
The sample 2 has a lowest value of SE corresponding to the least sample variability.
Step-by-step explanation:
As the value of the sample means and standard deviations are not given, as similar question is found online from which the values of data is follows
The data is as attached with the solution. From this data
Sample 1 has a mean of 34 and a SE of 5
Sample 2 has a mean of 30 and a SE of 2
Sample 3 has a mean of 26 and a SE of 3
Sample 4 has a mean of 38 and a SE of 5
As per the measure of the sample variability is linked with the value of SE or standard error. Which is lowest in the case of sample 2 .
So the sample 2 has a lowest value of SE corresponding to the least sample variability.
1) Let x be the original speed that he was driving;
x mph ---> 1.5 hours
x+44 mph --> 2.5 hours
1.5x + 2.5(x+44)=206
1.5x+2.5x+110=206
4x=206-110
4x=96
x=24
Therefore, he was travelling at 24 mph in the fog.
2) Let x be the speed of 1 snail,
The other snail travels at the speed of x+1 cm/min
23x+23(x+1)=391 <-- solve for x
23x+23x+23=391
46x=368
x=368/46
x=8
Therefore one of the snail travels at 8 cm/min while the other goes at 9 cm/min
7) Let x be one crew
Then the other crew would be working at x+0.5
3.2x+3.2(x0.5)=8 <-- solve for x
3.2x+1.6x=8
4.8x=8
x=8/4.8
x=1.6666 or 1.7 miles
Therefore, one of the crew does 1.7 miles per day and the other crew does (0.5*1.7)=0.85 miles
Hope I helped :)
Answer:
Adults $ 17
Students: $8
Step-by-step explanation:
Adults: x
Students: y
a) 25x + 31y = 673
b) 27x +31y = 707
Elimination:
a) -1(25x + 31y = 673) = -25 -31y = -673
a + b
= (-25 -31y = -673) + (27x + 31y = 707)
= 2x = 34
x = 34/2
x = 17
Substitution a or b:
a) 25(17) + 31y = 673
425 + 31y = 673
31y = 673 - 425
31y = 248
y = 248/31
y = 8
