Answer:
B. acute, isosceles
Step-by-step explanation:
The two small lines intersecting the two sides stand for congruency.
Two sides are congruent, so this is an isosceles triangle.
None of the angles here are greater or equal to 90 degrees, so it is an acute triangle.
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5x if x= 2/5 . 5/1x 2/5= 10/5= 2
5/x = 5/5= 1
8/3_ 1 = 8/3- 3/3= 5/3
1/2+ 3/4 = 2/4+3/4= =5/4
9) Separate the polygon into 2 shapes (a rectangle and triangle). Then plug in the formula for those 2 shapes separately and add the 2 areas.
First, the triangle's area = bh x 1/2 or bh/2.
b=5 and h=5, so 5x5/2 or 25/2 = 12.5.
Next, solve the area for the rectangle(lw=A). l=5 and 2=8, so 5x8=40.
Add 40 +12.5 = 52.5cm^2 (always include units).
10) It is similar to the last problem. You will separate the polygon into 2 shapes (a circle and a square), but this time you will subtract the area of the sector formed from the circle (draw a dotted line where the circle would be formed in the square).
So, the area of the square is 2x2=4ft^2.
area of a circle is (pi)r2 or (pi)2^2= 4pi or about 12.5ft^2.
4+12.5 = 16.5 ft^2.
Now, the area of the sector must be subtracted from the combination of the 2 areas found above.
The area of a sector is 2(pi)r x (C/360).
The angle is given as 90°, the radius is 2 ft. Now plug these into the equation.
2(pi)(2)x(90/360) = 3.14ft^2.
16.5-3.14= 13.4 ft^2.
Answer:13
Step-by-step explanation:
