What is the median for the following set of data?<br><br> 5, 7, 9, 11, 13, 13

grandymaker [24]

The solution is....................

5 0

3 years ago

If the height and base of the parallelogram shown are each decreased by 2 cm, what is the area of the new parallelogram?

marusya05 [52]

complete question:

If the height and base of the parallelogram shown are each decreased by 2 cm, what is the area of the new parallelogram?

A parallelogram with a base of 10 centimetres and a height of 8 centimetres.

Answer:

area = 48 cm²

Step-by-step explanation:

A parallelogram is quadrilateral with 4 sides formed by 2 pair of parallel lines. The area of a parallelogram is represented as follows :

area of parallelogram = B × H

where

B = breadth

H = height

According to the question the height and the base each reduced by 2 cm.

The new base = 10 - 2 = 8 cm

The new height = 8 - 2 = 6 cm

area = B × H

area = 8 × 6

area = 48 cm²

7 0

3 years ago

$650 is invested in an account earning 8.6% interest (APR), compounded monthly. Write a function showing the value of the accoun

IRISSAK [1]

Answer:

The value of the acount after t years is of $A(t) = 650(1.0072)^{12t}$

The annual growth rate is of 0.72%.

Step-by-step explanation:

Compound interest:

The compound interest formula is given by:

$A(t) = P(1 + \frac{r}{n})^{nt}$

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

$650 is invested in an account earning 8.6% interest (APR), compounded monthly.

This means that $P = 650, r = 0.086, n = 12$ . So

$A(t) = P(1 + \frac{r}{n})^{nt}$

$A(t) = 650(1 + \frac{0.086}{12})^{12t}$

$A(t) = 650(1.0072)^{12t}$

The value of the acount after t years is of $A(t) = 650(1.0072)^{12t}$

Annual growth rate

1.0072 - 1 = 0.0072 = 0.72%

The annual growth rate is of 0.72%.

5 0

3 years ago

According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are re

Luda [366]

Answer:

The questions asked are

If you randomly select 4 peanuts

1. Compute the probability that exactly three of the four M&M’s are brown

2. Compute the probability that two or three of the four M&M’s are brown.

3. Compute the probability that at most three of the four M&M’s are brown.

4. Compute the probability that at least three of the four M&M’s are brown.

Step-by-step explanation:

Given the following information

Brown=12%. P(B)=0.12

Yellow=15%. P(Y)=0.15

Red=12%. P(R), =0.12

Blue=23%. P(B) =0.23

Orange, =23%. P(O) =0.23

Green=15%. P(G)=0.15

Question 1.

They are independent events

If there are exactly three brown and the last is not brown

P(B n B n B n B')

P(B)×P(B)×P(B)×P(B')

0.12×0.12×0.12×(1-P(B))

0.001728×(1-0.12)

0.001728×0.88

0.00152.

0.152%

2. If two or three are brown

I.e we are going to two brown and two none brown or three brown and one not brown. (P(B)×P(B)×P(B')×P(B'))+ (P(B)×P(B)×P(B'))

(0.12×0.12×0.88×0.88)+(0.12×0.12×0.12×0.88)

0.0112+0.00152

0.0127

1.27%

3. At most three brown out of four then we are going to have

BBBB', BBB'B', BB'B'B', B'B'B'B'

These are the cases of at most three brown.

P(B)×P(B)×P(B)×P(B') + P(B)×P(B)×P(B')×P(B') + P(B)×P(B')×P(B')×PB')+ P(B')×P(B')×P(B')×P(B')=

0.12×0.12×0.12×0.88+ 0.12×0.12×0.88×0.88+ 0.12×0.88×0.88×0.88+ 0.88×0.88×0.88×0.88=0.694

0.694

69.4%

4. At least 3 brown out of four selection

I.e BBBB', BBBB

These are the two options

P(B)×P(B)×P(B)×P(B') + P(B)×P(B)×P(B)×P(B)=

0.12×0.12×0.12×0.88 + 0.12×0.12×0.12×0.12

0.001728

0.173%

4 0

3 years ago

Read 2 more answers

3(x - 5) = 30<br> I dont know how to solve this

Anastaziya [24]

Answer:

x=15

Step-by-step explanation:

3(x-5)=30

First, you would distribute the three to the x and the negative five.

3x-15=30

Then you would add 15 to the 15 to cancel it and to the 30 to make it even.

3x-15=30

+15=+15=

3x=45

Finally, you would divide 3 into both sides, cancelling out the three and fiving you,

x=15

Hope this helped!

3 0

3 years ago

Read 2 more answers

What is the median for the following set of data? 5, 7, 9, 11, 13, 13