A.) P(defective | foo) = P(defective & foo)/P(foo)
4% = P(defective & foo)/30% . . . . . . . . . plug in the given data
0.04*0.30 = P(defective & foo) = 0.012 = 1.2%
The probability that a widget was produced at the foo factory and is defective is 1.2%.
b.) P(defective | foo) ≠ P(defective) (4% ≠ 5%), so the events P(defective) and P(foo) are NOT independent.
c.) P(foo | defective) = P(defective & foo)/P(defective)
P(foo | defective) = 1.2%/5% = 24%
The probability that a widget was produced at the foo factory given it is defective is 24%.
Answer:
45
Step-by-step explanation:
We can first expand the expression:
n(n+p) - n
= n^2 + np + n
Then, we can plug in values of n and p into the expression:
n^2 + np + n = (5)^2 + (5)(3) + 5 = 25 + 15 + 5 = 45
Answer:
Acute Triangle
Step-by-step explanation:
An acute is 30 so 30+30-60.
