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gregori [183]
4 years ago
9

Please HELP with congruence problem!!!

Mathematics
1 answer:
faust18 [17]4 years ago
5 0
The answer that will not result in a congruent figure is the statement about moving the points so they are 2/3 as far from the y-axis.

If you take the 2 top points on the trapezoid and test this, you will see they will not end up the same distance apart.  Currently, they are 3 units apart.

2/3 of 6 = 4 units from the y-axis
2/3 of 3 = 2 units from the y-axis

This new figure would only be 2 units apart on the top.
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Use the diagram to answer the questions​
harkovskaia [24]

Answer:

sorry

Step-by-step explanation:

 

5 0
3 years ago
HELP I WILL MAEK BEAINLIST PLEASE
wolverine [178]

Answer:

260,548668 or 260.55 round to the nearest hundreds  

Step-by-step explanation:

Area of the trapezoid:

[(major base + minor base)x height]/2

[(22 + 12) x 12]/2 = 204 cm^2

radius = diameter / 2 = 12 / 2 = 6 cm

Area of a semicircle

(radius^2 x pi)/2 = (6^2 x pi)/2 = 56.548668 cm^2

total area = 204 + 56,548668 = 260,548668 cm^2

6 0
3 years ago
A car is traveling in a race. The car went from the initial velocity of 35 m/s to the final velocity of 65m/s in 5 seconds what
artcher [175]

The acceleration is defined as the ratio between the change in velocity and the time elapsed to perform such a change.

These "changes" are indicated with the capital greek letter delta, \Delta, and when you write \Delta x you mean the difference between the finial and the inital values of the variable x:

\Delta x = x_{\text{fin}} - x_{\text{init}}

So, the acceleration is defined as

a = \dfrac{\Delta v}{\Delta t} = \dfrac{v_{\text{fin}} - v_{\text{init}}}{t_{\text{fin}} - t_{\text{init}}}

In this case, the initial velocity is 35, the final velocity is 65. Assuming we start the clock at the beginning of the observation, the inital time is 0 and the final time is 5. So, we have

a = \dfrac{65-35}{5-0} = \dfrac{30}{5} = 6m/s^2

3 0
3 years ago
Read 2 more answers
8x + 20y = 20<br> 14x + 35y = k<br> For the above system of equations to be consistent, k must equal
Goshia [24]

Answer:

  35

Step-by-step explanation:

The equations will be "consistent" when they describe lines that are not parallel.

<h3>Slopes</h3>

The slope of a line whose equation is written in this form is the opposite of the ratio of the y-coefficient to the x-coefficient:

  line 1 slope = -8/20 = -2/5

  line 2 slope = -14/35 = -2/5

These lines have the same slope, so will be parallel unless they have the same y-intercept.

<h3>Y-intercept</h3>

The y-intercept of each line is the ratio of the constant to the y-coefficient:

  line 1 y-intercept = 20/20 = 1

  line 2 y-intercept = k/35

We want these lines to have the same y-intercept so that they are not inconsistent. This requires ...

  k/35 = 1

  k = 35

For the equations to be consistent, we must have k = 35.

__

<em>Additional comment</em>

Linear equations are generally categorized as "consistent" or "inconsistent," and "dependent" or "independent."

Equations are "inconsistent" if there are no values of the variables that satisfy all of the equations. They are "dependent" if they describe exactly the same relation between the variables. "Consistent" equations may be "dependent" (describing the same line, as here), or "independent" (describing lines with different slopes.)

7 0
2 years ago
17+4h+2=1-5h what does the variable equal ?
olga2289 [7]
1. 17+4h+2=1-5h
2. 19+4h=1-5h
3. 18+4h=-5h
4. 18=-9h
5. -2=h
5 0
3 years ago
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