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Shtirlitz [24]
3 years ago
13

There were 287 music books and 134 science books in the store. After some books were sold there are 159 books left. How many boo

ks were sold?
Mathematics
2 answers:
stiks02 [169]3 years ago
4 0

Answer:

262 books sold

Step-by-step explanation:

This is a very vague word problem, but if it truly is just asking the amount of books sold (regardless of music or science), here's how to get the answer:

1. 287+134=421 - first you want to add together the two types of books to get the total amount of books in the store

2. 421-x=159 - create an equation and solve.

3. -x=-262 - follow order of operations and subtract 421 on both sides in order to isolate the variable

4. x=262 - divide each side by -1 to make the variable positive.

If you'd like an easier way, you can just:

1. 421-159=262 - it's easier, but my math teacher would count us wrong if we didn't do equations a specific way. Good luck!

Black_prince [1.1K]3 years ago
4 0
There were 262 books sold.
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Scores on the SAT Mathematics test are believed to be normally distributed. The scores of a simple random sample of five student
AysviL [449]

Answer:

The mean calculated for this case is \bar X=584

And the 95% confidence interval is given by:

584-2.776\frac{86.776}{\sqrt{5}}=476.271    

584+2.776\frac{86.776}{\sqrt{5}}=691.729    

So on this case the 95% confidence interval would be given by (476.271;691.729)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=584

The sample deviation calculated s=86.776

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that t_{\alpha/2}=2.776

Now we have everything in order to replace into formula (1):

584-2.776\frac{86.776}{\sqrt{5}}=476.271    

584+2.776\frac{86.776}{\sqrt{5}}=691.729    

So on this case the 95% confidence interval would be given by (476.271;691.729)    

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