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Mashutka [201]
3 years ago
11

At what angle do the angle bisectors of two same side interior angles intersect in construction with two parallel lines and a tr

ansversal?
Mathematics
1 answer:
jeka943 years ago
3 0
Same-side interior angles are a pair of angles on one side of a transversal line, and on the inside of the two parallel lines being intersected.

The sum of same-side interior angles is equal to 180 degrees.

A transversal line is a line that intersects other lines.

Parallel lines are lines that run alongside each other that never intersect.

An angle bisector is a line that divides an angle into two equal parts.

Given that the sum of same side interior angles is equal to 180 degrees, then the sum of the angle formed by the angle bisector is equal to 90 degrees.
Thus the angle bisectors intersect at an angle 90 degrees.

Therefore, the angle bisectors <span>of two same side interior angles in construction with two parallel lines and a transversal</span> intersect at angle 90 degrees.



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Cathy has $100 saved to spend on clothes. She wants to purchase a winter jacket for $40 and some sweaters that cost $20 each. Ho
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Step-by-step explanation: Is (5, 5) a solution to the equation y=x ?
enyata [817]

Answer:

Yes, (5,5) is a solution of y=x

Step-by-step explanation:

A point is given as a coordinate pair, (x,y). The first number is x and the second number is y. A solution is a pair of numbers that will make the equation true.

To check if the point is a solution, fill in the first number in place of x in the equation. Then fill in the second number for the y.

Here we have the equation:

y = x

Substituting (filling in) we get:

5 = 5 a true statement. So (5,5) IS a solution.

Alternatively, you could graph the equation and verify that the point is on the graph. see image.

7 0
2 years ago
What do they call a number that goes on forever?
Art [367]
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3 0
4 years ago
Read 2 more answers
What are the zeros of the quadratic function f(x) = 2x2 + 8x – 3? x = –2 – StartRoot StartFraction 11 Over 2 EndFraction EndRoot
Phantasy [73]

Answer:

The zeros are

x=-2+\frac{\sqrt{22}}{2}

x=-2-\frac{\sqrt{22}}{2}  

Step-by-step explanation:

we have

f(x)=2x^{2}+8x-3

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

Equate the function to zero

2x^{2} +8x-3=0  

so

a=2\\b=8\\c=-3

substitute in the formula      

x=\frac{-8\pm\sqrt{8^{2}-4(2)(-3)}} {2(2)}  

x=\frac{-8\pm\sqrt{88}} {4} 

x=\frac{-8\pm2\sqrt{22}} {4} 

x=-2\pm\frac{\sqrt{22}}{2}

therefore

x=-2+\frac{\sqrt{22}}{2}

x=-2-\frac{\sqrt{22}}{2}  

4 0
4 years ago
Read 2 more answers
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