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Mashutka [201]
3 years ago
11

At what angle do the angle bisectors of two same side interior angles intersect in construction with two parallel lines and a tr

ansversal?
Mathematics
1 answer:
jeka943 years ago
3 0
Same-side interior angles are a pair of angles on one side of a transversal line, and on the inside of the two parallel lines being intersected.

The sum of same-side interior angles is equal to 180 degrees.

A transversal line is a line that intersects other lines.

Parallel lines are lines that run alongside each other that never intersect.

An angle bisector is a line that divides an angle into two equal parts.

Given that the sum of same side interior angles is equal to 180 degrees, then the sum of the angle formed by the angle bisector is equal to 90 degrees.
Thus the angle bisectors intersect at an angle 90 degrees.

Therefore, the angle bisectors <span>of two same side interior angles in construction with two parallel lines and a transversal</span> intersect at angle 90 degrees.



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Answer:

80%

Step-by-step explanation:

30 divided by 6 is 5, therefor, 1/5 of the book club is made up of women, mean 4/5 of the book club is made up of men. 4/5 is equivalent to 8/10, which can be converted to 80%

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Find the positive base $b$ in which the equation $5_b \cdot 23_b = 151_b$ is valid.
DanielleElmas [232]

Answer:

b=7

Step-by-step explanation:

We want to determine the positive base b in which:

5_b \cdot 23_b = 151_b

The easiest way to approach this is to convert all the numbers to base 10.

5_b=5Xb^0=5\\23_b =(2Xb^1)+(3Xb^0)=2b+3\\151_b=(1Xb^2)+(5Xb^1)+(1Xb^0)=b^2+5b+1\\Therefore:\\5_b \cdot 23_b = 151_b\\5(2b+3)=b^2+5b+1\\10b+15=b^2+5b+1\\b^2+5b+1-10b-15=0

b^2-5b-14=0

Next, we factorize the resulting expression.

b^2-5b-14=b^2-7b+2b-14=0\\b(b-7)+2(b-7)=0\\(b-7)(b+2)=0\\b-7=0\: or \: b+2=0\\b=7\: or \: b=-2

The positive value of b for which the equality hold is 7.

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Step-by-step explanation:

You add. hope it helps ;)

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