Answer:
Which statement is true about biodiversity?
Human activity can improve, maintain, or hurt biodiversity
Explanation:
Biodiversity entails having different varieties of organism spread all over every habitat across the globe. Human activities could help biodiversity as well as reduce it drastically
Cancer cells are the cells that divide rapidly than any other cells in the body. The drugs used in chemotherapy work on rapidly dividing cancer cells. Some cells of our body apart from cancer cells also divide rapidly along with the cancer cells such as the cells that line the stomach and the digestive tract. Chemotherapy drugs cannot differentiate the cancer cells and the normal cells so these drugs also attack the normal cells which divide rapidly along with the cancer cells. The drugs also attack the cells that are present in the roots of the hair. So, this results in the hair loss. Hair loss does not occur immediately after the chemotherapy treatment instead it starts after few treatments. The degree of the hair loss after chemotherapy depends on the drug type and process. So when the chemotherapy drugs are used it results in the hair loss and nausea.
Therefore, when chemotherapy drugs attack normal cells including the roots of the hair instead of cancer cells that divide rapidly along with the cancer cells it results in the hair loss and nausea.
Answer: I believe the answer is C
Answer:
1) CO₂
2) 0.2551 g
Explanation:
The balanced reactions are:
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
MgCO₃ + 2HCl → MgCl₂ + H₂O + CO₂
1) The gas produced is CO₂.
2) Calculate mass of CaCO₃:
(0.5236 g) (0.4230) = 0.2215 g CaCO₃
Convert to moles:
(0.2215 g CaCO₃) (1 mol / 100.1 g) = 0.002213 mol CaCO₃
Find moles of CaCO₃:
(0.002213 mol CaCO₃) (1 mol CO₂ / mol CaCO₃) = 0.002213 mol CO₂
Convert to mass:
(0.002213 mol CO₂) (44.01 g / mol) = 0.09738 g CO₂
Calculate mass of MgCO₃:
(0.5236 g) (0.5770) = 0.3021 g MgCO₃
Convert to moles:
(0.3021 g MgCO₃) (1 mol / 84.31 g) = 0.003583 mol MgCO₃
Find moles of MgCO₃:
(0.003583 mol MgCO₃) (1 mol CO₂ / mol MgCO₃) = 0.003583 mol CO₂
Convert to mass:
(0.003583 mol CO₂) (44.01 g / mol) = 0.1577 g CO₂
Total mass of CO₂:
0.09738 g CO₂ + 0.1577 g CO₂ = 0.2551 g CO₂
