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2 years ago

What is the polynomial function of least degree whose only zeros are -3, ,-2, and 4 ?

Mathematics

1 answer:

victus00 [196]2 years ago

7 0

Answer: (x³ - 2x² - 11x + 12)

Step-by-step explanation:

Recall that zeroes can be transformed into factors by subtracting them from x. This gives us the following factors:

(x - 1)(x + 3)(x - 4)

Now, if you multiply the first two factors together, you get the following:

(x² + 2x - 3)

Multiply that by the last factor, (x - 4), and you get this:

(x³ + 2x² - 3x - 4x² - 8x + 12)

This can be simplified:

(x³ - 2x² - 11x + 12)

And there's your final answer. Hope this helped! (x³ - 2x² - 11x + 12)

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Step-by-step explanation:

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2 years ago

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The equation is $c-13=-2$

The solved equation is 11

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2 years ago

What is an equation in slope-intercept form of the line that passes through (6, 10) and is parallel to the graph of y=13 x−1 ?

nadezda [96]

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2 years ago

the height of a house having three rooms of the dimensional 9 feet into 12 feet 14 feet into 16 feet and 12 feet into 14 feet re

Semmy [17]

Answer:

Amount required = 2,217,600

Step-by-step explanation:

Dimensions of the rooms are as follows;

Room 1; 9 feet × 12 feet

Room 2; 14 ft × 16 ft

Room 3; 12 ft × 14 ft

Perimeter of rooms;

P1 = 2(9 + 12) = 42 ft

P2 = 2(14 + 16) = 60 ft

P3 = 2(12 + 14) = 52 ft

Total perimeter; P = 42 + 60 + 52 = 154 ft

Height is 90 ft.

Thus, total area is;

A = 154 × 90

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Rate of painting is 160 per Sq.ft.

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2 years ago

What are the real zeros of x^3+4x^2-9x-36

Katyanochek1 [597]

Answer:

$x = -4\\x = -3\\x = 3$

Step-by-step explanation:

To find the real zeros you must match the function to zero and factor the expression.

We have a polynomial of degree 3.

We try to group the terms to perform the factorization

$x ^ 3 + 4x ^ 2-9x-36 = 0\\\\x ^ 2(x + 4) - 9(x + 4) = 0$

Now we take (x + 4) as a common factor

$(x + 4)(x ^ 2 -9) = 0$

If we have an expression of the form $(a ^ 2-b ^ 2)$ we know that this expression is equivalent to:

$(a ^ 2-b ^ 2) = (a + b)(a-b)$

In this case

$a = x\\b = 3$

So:

$(x ^ 2 -9) = (x + 3)(x-3)$

Finally:

$x ^ 3 + 4x ^ 2-9x-36 = (x + 4)(x + 3)(x-3) = 0$

The solutions are:

$x = -4\\x = -3\\x = 3$

6 0

2 years ago