In this question, Suzan is taking 5 marble from a bag containing 4 red marbles, 3 green ones, 4 white ones, and 3 purple ones. The total marble in the bag should be: 4+3+4+3= 14. The question is how much the probability to get <span>1 red, 2 green, 1 white and 1 purple.
Ways to take 5 marble out of 14=14C5= 14!/5!9!= </span>2002<span>
</span>Ways to take 1 red marble out of 4= 4C1= 4<span>
</span>Ways to take 2 green marble out of 3= 3C2= 3
Ways to take 1 white marble out of 4= 4C1= 4
Ways to take 1 purple marble out of 3= 3C1= 3
Then the probability would be: 4*3*4*3/ 2002= 144/2002= 72/1001
Answer:
4/11 is already simplified as much as it can be in fraction form. as a percent its 36.3636%
Step-by-step explanation:
In below formula for arithmetic sequence you can fill in a=7 (start), d=2 (interval) and n=35 (nr terms) and you get
17.5(14 + 34*2) = 1435
Confirmed by a brute-force addition: 7+9+11+13+15+17+19+21+23+25+27+29+31+33+35+37+39+41+43+45+47+49+51+53+55+57+59+61+63+65+67+69+71+73+75=1435
What? Can you attach a photo?
Answer:
AC = 52
Step-by-step explanation:
Add the segment lengths together.
AB + BC = AC
22 + 30 = 52