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Temka [501]
3 years ago
9

The dosage for a drug used to treat a male Siberian tiger that weighs 550 pounds is based on the tiger's weight in kilograms (kg

). What is the tiger's weight in kg? (1 kg = 2.2 lbs)
A) 200 kg
B) 250 kg
C) 300 kg
D) 500 kg
Mathematics
1 answer:
Klio2033 [76]3 years ago
3 0

Answer:

B) 250kg

Step-by-step explanation:

given that 1kg = 2.2lbs,

the 550lbs = 550/2.2 = 250kg

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Fill in the numbers to find a Sum
Alekssandra [29.7K]

Answer:

The numbers are -15 and 100

\frac{2}{10} +\frac{-15}{100} =\frac{5}{100}

Step-by-step explanation:

we have

\frac{2}{10} +\frac{x}{100} =\frac{5}{y}

Solve the left side

\frac{2}{10} +\frac{x}{100} =\frac{20+x}{100}

so

\frac{20+x}{100}=\frac{5}{y}

equate the numerators and the denominators

20+x=5 ------> x=5-20=-15

100=y -------> y=5

therefore

The numbers are -15 and 100

\frac{2}{10} +\frac{-15}{100} =\frac{5}{100}

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3 years ago
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Log20
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Midpoint of (16,5) and (-6,-9)?
Zigmanuir [339]

To solve this problem, we need to use the midpoint formula, where M = (x1+x2/2, y1+y2/2). To solve, we must plug in the given (x,y) values from our ordered pairs and then simplify, shown below:

(x1+x2/2, y1+y2/2)

( (16 + -6)/2, (5 + -9)/2 )

Now, we can begin to simplify by computing the addition in the numerators of both fractions.

(10/2, -4/2)

Next, we can finish the simplification process by dividing these fractions.

(5, -2)

Therefore, the midpoint of (16,5) and (-6,-9) is (5,-2).

Hope this helps!

8 0
3 years ago
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Step-by-step explanation:

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svp [43]

Answer:

c. The Mean of Normal Distribution is related to the average of the data set. The Standard deviation is related to data variation.

Step-by-step explanation:

(a) No, mean don't tell us how much the data deviate from the average, Standard deviation tells us. So, Option (a) is incorrect.

(b) No, mean is greatly affected by extreme values. But Median is good to measure central tendency when there is outlier present in data. So, Option (b) is also incorrect.

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Further, Mean is used to measure the central tendency of data which represents the whole data in the best way. It can be found as the ratio of the sum of all the observations to the total number of observations.

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