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Leya [2.2K]
3 years ago
10

A number, y, is equal to twice the sum of a smaller number and 3. The larger number is also equal to 5 more than 3 times the sma

ller number. Which equations represent the situation?
Mathematics
2 answers:
goblinko [34]3 years ago
6 0

Answer:

A

Step-by-step explanation:

I took the test on edge just trust me...

I HOPE THIS HELPS

Nata [24]3 years ago
3 0

Answer:

The equations represent the situation is y=2x+6 and y=5+3x.

Step-by-step explanation:

Consider the provided information.

First convert the statement into mathematical representation.

Consider the smaller number is <em>x</em> and the larger number is <em>y</em>.

<em>y</em>, is equal to twice the sum of a smaller number and 3.    

This information can be written as: y=2(x+3)

Which can be further solve as:

y=2x+6

The larger number is also equal to 5 more than 3 times the smaller number.

This information can be written as: y=5+3x

Thus, the equations represent the situation is y=2x+6 and y=5+3x.

Which can be further solve as:

2x+6=5+3x

x=1

Now, substitute the value of <em>x</em> in y=5+3x.

y=5+3

y=8

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Taking y=y(x) and differentiating both sides with respect to x yields

\dfrac{\mathrm d}{\mathrm dx}\bigg[3x^2+y^2\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[7\bigg]\implies 6x+2y\dfrac{\mathrm dy}{\mathrm dx}=0

Solving for the first derivative, we have

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Differentiating again gives

\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0

Solving for the second derivative, we have

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Now, when x=1 and y=2, we have

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