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3 years ago

How much did Elizabeth invest?

Mathematics

2 answers:

spayn [35]3 years ago

8 0

Answer:

Option D is the nearest answer.

Elizabeth invested = $45,714

Step-by-step explanation:

Given that:

Total amount = $80,000

Ratio given = 3:4

As the total is divided into 7 parts (3+4) so,

Each part equals = 80,000/7

Each part equals = 11,428.57

Now steive invested = 11,428.57 * 3 = $34,286

Elizabeth invested= 11,428.57*4 = $45,714

i hope it will help you

Tresset [83]3 years ago

8 0

Yeah, I think it is C...

I don't really have an explanation though.

If I'm wrong, correct me. Hope I helped! ☺☼

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I need help with questions #7 and #8 plz

katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

$c^2 = a^2 + b^2 - 2ab \cos C$

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

We use the law of cosines to find C.

$18^2 = 12^2 + 16^2 - 2(12)(16) \cos C$

$324 = 144 + 256 - 384 \cos C$

$-384 \cos C = -76$

$\cos C = 0.2$

$C = \cos^{-1} 0.2$

$C = 78.6^\circ$

Now we use the law of sines to find angle A.

Law of Sines

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

We know c and C. We can solve for a.

$\dfrac{a}{\sin A} = \dfrac{c}{\sin C}$

$\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}$

Cross multiply.

$18 \sin A = 12 \sin 78.6^\circ$

$\sin A = \dfrac{12 \sin 78.6^\circ}{18}$

$\sin A = 0.6535$

$A = \sin^{-1} 0.6535$

$A = 40.8^\circ$

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

$a^2 = b^2 + c^2 - 2bc \cos A$

$b^2 = a^2 + c^2 - 2ac \cos B$

$c^2 = a^2 + b^2 - 2ab \cos C$

Find angle A:

$a^2 = b^2 + c^2 - 2bc \cos A$

$8^2 = 18^2 + 12^2 - 2(18)(12) \cos A$

$64 = 468 - 432 \cos A$

$\cos A = 0.9352$

$A = 20.7^\circ$

Find angle B:

$b^2 = a^2 + c^2 - 2ac \cos B$

$18^2 = 8^2 + 12^2 - 2(8)(12) \cos B$

$324 = 208 - 192 \cos A$

$\cos B = -0.6042$

$B = 127.2^\circ$

Find angle C:

$c^2 = a^2 + b^2 - 2ab \cos C$

$12^2 = 8^2 + 18^2 - 2(8)(18) \cos B$

$144 = 388 - 288 \cos A$

$\cos C = 0.8472$

$C = 32.1^\circ$

8 0

3 years ago

Maya had $27. She spent all the money on buying 3 burgers for $x each and 2 sandwiches for $y each. If Maya would have bought 2

defon

Answer:

Option C

The student's conclusion is correct because the solution to the system of equations $3x+2y=27$ and $2x+y=16$ is $(5,6)$

Step-by-step explanation:

Let

x------> the cost of each burger

y-----> the cost of each sandwich

we know that

$3x+2y=27$ -----> equation A

$2x+y=(27-11)$

$2x+y=16$ ----> equation B

Solve the system of equations

Multiply the equation B by $-2$

$-2(2x+y)=-2*16$ -----> $-4x-2y=-32$ ------> equation C

Adds equation A and equation C

$3x+2y=27 \\-4x-2y=-32\\ ----------\\ 3x-4x=27-32\\ -x=-5\\x=5$

Substitute the value of x in the equation B

$2(5)+y=16$

$10+y=16$

$y=6$

The solution of the system of equations is the point $(5,6)$

The price of each burger is $\$5$

The price of each sandwich is $\$6$

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Simplify the following expression:<br> 4x - 3y + 2z - 3x - y + 3z = ?

nordsb [41]

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