What is the square root of 1,234,137,927,888

2 Points

sasho [114]

Answer:

x-3

Step-by-step explanation:

f(x) = 3x - 2

g(x) = 2x + 1,

(f- g)(x) = 3x - 2 - ( 2x+1)

Distribute

= 3x -2 -2x-1

Combine like terms

x-3

4 0

4 years ago

According to records in a large hospital, the birth weights of newborns have a symmetric and bell-shaped relative frequency dist

Kamila [148]

Answer:

15.9% of babies are born with birth weight under 6.3 pounds.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.8 pounds

Standard Deviation, σ = 0.5

We are given that the distribution of birth weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(birth weight under 6.3 pounds)

P(x < 6.3)

$P( x < 6.3) = P( z < \displaystyle\frac{6.3 - 6.8}{0.5}) = P(z < -1)$

Calculation the value from standard normal z table, we have,

$P(x < -1) = 0.159 = 15.9\%$

15.9% of babies are born with birth weight under 6.3 pounds.

8 0

3 years ago

from the top of a tree the angle of depression of a rock on the ground is 49 degrees. If the tree is 18.5 m tall, how far is the

Rashid [163]

Answer:

Step-by-step explanation:

If you were to sit in the very top of said tree and look directly straight, your line of vision would be parallel to the ground. The angle of depression is in between your line of vision and the rock. When you look down at the rock, your line of vision to the rock is a transversal between the 2 parallel lines. With this being the case, the angle of depression is alternate interior with the angle made on the ground from the rock to the top of the tree. See the illustration I attached below.

We are looking for the distance on the ground between the tree and the rock, which we will call x. The side opposite the reference angle is the height of the tree and the side adjacent to the reference angle is x. Side opposite over side adjacent is the tangent ratio. Therefore,

$tan(49)=\frac{18.5}{x}$ and

$x=\frac{18.5}{tan(49)}$ and on your calculator in degree mode, you will find that

x = 16.08 m

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4 0

3 years ago

A trough of water is 20 meters in length and its ends are in the shape of an isosceles triangle whose width is 7 meters and heig

Vaselesa [24]

Answer:

a) Depth changing rate of change is $0.24m/min$ , When the water is 6 meters deep

b) The width of the top of the water is changing at a rate of $0.17m/min$ , When the water is 6 meters deep

Step-by-step explanation:

As we can see in the attachment part II, there are similar triangles, so we have the following relation between them $\frac{3.5}{10} =\frac{a}{h}$ , then $a=0.35h$ .

a) As we have that volume is $V=\frac{1}{2} 2ahL=ahL$ , then $V=(0.35h^{2})L$ , so we can derivate it $\frac{dV}{dt}=2(0.35h)L\frac{dh}{dt}$ due to the chain rule, then we clean this expression for $\frac{dh}{dt}=\frac{1}{0.7hL}\frac{dV}{dt}$ and compute with the knowns $\frac{dh}{dt}=\frac{1}{0.7(6m)(20m)}2m^{3}/min=0.24m/min$ , is the depth changing rate of change when the water is 6 meters deep.

b) As the width of the top is $2a=0.7h$ , we can derivate it and obtain $\frac{da}{dt}=0.7\frac{dh}{dt} =0.7*0.24m/min=0.17m/min$ The width of the top of the water is changing, When the water is 6 meters deep at this rate

8 0

3 years ago

Two large numbers of the Fibonacci sequence are F49 = 7,778,742,049 and F50 = 12,586,269,025. What is the approximate value of t

Lina20 [59]

Two large numbers of the Fibonacci sequence are F49<span>= </span>7778742049 and F50=12586269025<span>.</span>

4 0

3 years ago