9514 1404 393
Answer:
(c) 1.649
Step-by-step explanation:
For a lot of these summation problems it is worthwhile to learn to use a calculator or spreadsheet to do the arithmetic. Here, the ends of the intervals are 1 unit apart, so we only need to evaluate the function for integer values of x.
Almost any of these numerical integration methods involve some sort of weighted sum. For <em>trapezoidal</em> integration, the weights of all of the middle function values are 1. The weights of the first and last function values are 1/2. The weighted sum is multiplied by the interval width, which is 1 for this problem.
The area by trapezoidal integration is about 1.649 square units.
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In the attached, we have shown the calculation both by computing the area of each trapezoid (f1 does that), and by creating the weighted sum of function values.
Answer:
4(90) + 4(2)
Step-by-step explanation:
The given expression is 4(92)
This can be expressed as
This can also be expressed as
Using the distributive law of multiplication and additon,
a*(b+c) = a*b + a*c
In this case a=4
b=90 and c = 2
So the equivalent expression is
But this is the same as option 2 in the list of given options.
Hence the equivalent expression is 4(90) + 4(2)