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3 years ago

I need help please! Ap calculus

Mathematics

1 answer:

Vika [28.1K]3 years ago

4 0

9514 1404 393

Answer:

Step-by-step explanation:

For a lot of these summation problems it is worthwhile to learn to use a calculator or spreadsheet to do the arithmetic. Here, the ends of the intervals are 1 unit apart, so we only need to evaluate the function for integer values of x.

Almost any of these numerical integration methods involve some sort of weighted sum. For <em>trapezoidal</em> integration, the weights of all of the middle function values are 1. The weights of the first and last function values are 1/2. The weighted sum is multiplied by the interval width, which is 1 for this problem.

The area by trapezoidal integration is about 1.649 square units.

In the attached, we have shown the calculation both by computing the area of each trapezoid (f1 does that), and by creating the weighted sum of function values.

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

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You draw a card at random from a standard deck of 52 cards. Find the following conditional probabilities: a.) The probability th

Levart [38]

Answer:

a.) 1/2 or 50%

b.) 1/1 or 100%

c.) 1/13 or 7.69%

d.) 1/3 or 33.33%

Step-by-step explanation:

a.) The probability that a card is a heart, given that it is red?

There are four suits in a deck, two of which are red: hearts and diamonds. Since the number of hearts and diamonds is the same, the probability of the card being a heart, given that it is red is 1/2 or 50%.

b.) The probability that a card is red, given that it is a heart?

All hearts are red cards, therefore, given the card is a heart, there is a 1/1 or 100% probability that it is red.

c.) The probability that a card is a king, given that it is red?

There are 26 red cards, 2 of which are kings. Therefore, the probability of a card being a king, given that it is red is 1/13 or 7.69%.

d.) The probability is a queen, given that it is a face card?

There are 12 face cards in a deck, 4 of which are queens. Therefore, the probability of a card being a queen, given that it is a face card is 4/12 or 1/3 or 33.33%.

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4 years ago

7s^0t^-5/2^-1m^2 Simplify

expeople1 [14]

Answer: hope this helps

6 0

2 years ago

probability that cars have been assembled in a particular plant as follows: P(plant1)=20% , P(plant 2)=24% , P(plant 3.25% , P(p

Bogdan [553]

Answer:

16800/year

Step-by-step explanation:

Plant 1= 20%

Plant 2 = 24%

Plant 3 = 25%

Plant 4 = 31%

Total cars produced 100% = 1,200,000

Number of cars produced in plant 1 =

20% of 1,200,000 = 0.2 x 1,200,000 = 240,000 cars

Number of cars produced in plant 2 =

24% of 1,200,000 = 0.24 x 1,200,000 = 288,000 cars

Number of cars produced in plant 3 =

25% of 1,200,000 = 0.25 x 1,200,000 = 300,000 cars

Number of cars produced in plant 4 =

31% of 1,200,000 = 0.31 x 1,200,000 = 372,000 cars

Number of cars with no warranty claim in plant 1/year 223200

Number of cars with warranty claims in plant 1 + number of cars with no warranty claim in plant 1 = total number of cars produced in plant 1

X + 223200 = 240000

X = 240000 - 223200

X = 16800/year

number of cars with warranty claim in plant 1/ year is 16800

6 0

3 years ago