Question

If f(x) = 3x2 + 1 and g(x) = 1 – x, what is the value of (f – g)(2)?

Answer 1

Hello,

(f-g)(x)=3x²+1-1+x=3x²+x
(f-g)(2)=3*2²+2=3*4+2=14

Answer 2

Answer:

The value of (f-g)(2)= 14

Step-by-step explanation:

 f(x) = 3x^2 + 1 and g(x) = 1 – x

we need to find the value of (f-g)(2)

(f-g)(x)= f(x) - g(x)

Replace f(x) and g(x)

$(f-g)(x)= f(x) - g(x)= (3x^2+1 -(1-x))= 3x^2+1-1+x= 3x^2+x$

Now plug in 2 for x

$(f-g)(x) =3x^2+x$

$(f-g)(2) =3(2)^2+2=12+2=14$

The value of (f-g)(2)= 14