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3 years ago

A triangle with sides of lengths 9,22 and 24 is a right triangle True or false

Mathematics

2 answers:

olya-2409 [2.1K]3 years ago

8 0

Answer:

False

Step-by-step explanation:

Test this theory by using the pythagorean theorem.

for a right triangle with sides a, b and c

if c is they hypotenuse (i.e longest side) then the following must be true:

a² + b² = c² or c = √(a² + b²)

in this case, we assume the longest side to be c=24

also assume a=9 and b = 22

√ (a² + b² )

= √ (9² + 22² )

= √(81 + 484)

= √565

= 23.77 (close but NOT quite 24)

Hence this is NOT a right triangle.

Dmitry [639]3 years ago

5 0

Answer:

False

Step-by-step explanation:

If the triangle is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2

9^2 + 22^2 = 24^2

81+484=576

565 = 576

This is false, so the triangle is not a right triangle

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For the month of March in a certain city, 57% of the days are cloudy. Also in the month of March in the same city, 55% of th

kirill115 [55]

Answer:

P(F | C) = 0.96

Step-by-step explanation:

Hi!

This is a problem on conditional probability. Lets call:

C = { cloudy day }

F = { foggy day }

Then F ∩ C = { cloudy and foggy day }

You are asked for P(F | C), the probability of a day being foggy given it is cloudy. By definition:

$P(F|C)=\frac{P(F\bigcap C)}{P(C)}$

And the data you have is:

$P(C) = 0.57\\P(F \bigcap C) =0.55$

Then: P(F | C) = 0.96

3 0

3 years ago

Find the perimeter of a field that has length 2/x + 1 and width 5/x^2 -1.

Semmy [17]

Answer:

D)4x + 6/(x + 1)(x - 1)

Step-by-step explanation:

A field is basically a rectangle, so to find the perimeter of our field we are using the formula for the perimeter of a rectangle

$p=2(l+w)$

where

$p$ is the perimeter

$l$ is the length

$w$ is the width

We know from our problem that the field has length 2/x + 1 and width 5/x^2 -1, so $l=\frac{2}{x+1}$ and $w=\frac{5}{x^2-1}$ .

Replacing values:

$p=2(l+w)$

$p=2(\frac{2}{x+1} +\frac{5}{x^2-1})$

Notice that the denominator of the second fraction is a difference of squares, so we can factor it using the formula $a^2-b^2=(a+b)(a-b)$ where $a$ is the first term and $b$ is the second term. We can infer that $a=x^2$ and $b=1^2$ . So, $x^2-1=(x+1)(x-1)$ . Replacing that: