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juin [17]
3 years ago
5

Evaluate the expression a2+6ab for a=−3 and b=4.

Mathematics
1 answer:
inn [45]3 years ago
5 0
First you plug in the variables:

(-3)(2)+(6)(-3)(4)

Multiply:
-6+(-18)(4) 
-6+-72

Add and your answer comes out to be:
-78

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Calculate the volume of the cylinder. Use button, not 3.14. Round answer to the tenth place.
Volgvan

Answer:

68.69 m^3

Step-by-step explanation:

Volume of cone = \frac{1}{3}\pi r^{2}h

= \frac{1}{3}\pi (2.9^{2})(7.8)

= \frac{1}{3}\pi (65.6)\\

= \frac{1}{3}(206)

= 68.69 m^3

7 0
2 years ago
Madeleine says she can use a clock to show that 5/60 and 1/12 are equivalent fractions. Do you think she is correct? Explain.
Rasek [7]
Yes, 5/60, 5 divided by 5=1. 60 divided by 5= 12. Leaving you with 1/12. Meaning that both fractions are equivalent
5 0
3 years ago
Read 2 more answers
¿Look at the picture
kkurt [141]

Answer:

16.2 Kilometers

Step-by-step explanation:

81 divided by 5

You get 16.2 kilometers

8 0
3 years ago
ANSWER ASAP The area of a rectangle depends on its length and width. For the area to remain constant, the length varies inversel
Free_Kalibri [48]
Area of the rectangle is equal to length times width

In function notation, the Area of the rectangle function is a function in variables l (length) and w(width) as follows:

A(l, w)= l*w

for A=475 we have,

l*w=475

l= \frac{475}{w} or w= \frac{475}{l} , each are equivalent, and each represent the inverse variation.


Answer: l= \frac{475}{w} , w= \frac{475}{l} 


4 0
3 years ago
To pass this year's math class, Miriam needs to earn at least an 82%. Write an inequality that shows the scores Miriam could get
sergey [27]

The inequality that shows the scores Miriam could get to pass her math class is 82\%\leq x \leq 100\%

<em><u>Solution:</u></em>

Given that To pass this year's math class, Miriam needs to earn at least an 82%

To find: Inequality that shows the scores Miriam could get to pass her math class

Let "x" be the Miriam's score in the math class

Given she should score at least 82 %

Therefore, we can frame a inequality as:

x\geq 82 \%

Here we used "greater than or equal to" , because she can score 82 % or more than 82 % also

The maximum score is 100 %

Hence we can frame a inequality as:

x\leq 100 \%

Here, we used "less than or equal to" , because she can score the maximum score of 100 % or less than 100 %

Combining both the inequalities we get,

82\%\leq x \leq 100\%

All real numbers greater than or equal to 82% and less than or equal to 100%

Thus the required inequality is found

6 0
3 years ago
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