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juin [17]
3 years ago
5

Evaluate the expression a2+6ab for a=−3 and b=4.

Mathematics
1 answer:
inn [45]3 years ago
5 0
First you plug in the variables:

(-3)(2)+(6)(-3)(4)

Multiply:
-6+(-18)(4) 
-6+-72

Add and your answer comes out to be:
-78

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Find the value of the variables ​
Vedmedyk [2.9K]

Answer:

x = 15

y = 12

z = 20

Step-by-step explanation:

For right angle x^2 + z^2 = (9 + 16)^2 => x^2 + z^2 = 625

then z^2 = y^2 + 16^2 => y^2 = z^2 - 256

and x^2 = y^2 + 9^2 => y^2 = x^2 - 81

so z^2 - 256 = x^2 - 81

z^2 = x^2 + 175

replace z^2 = x^2 + 175 into the first equation

x^2 + (x^2 + 175) = 625

2x^2 = 450

x^2 = 225

x = 15

If x = 15 => 15^2 + z^2 = 625 => z^2 = 400 => z = 20

y^2 = z^2 - 256 => y^2 = 400 - 256 = 144

then y = 12

8 0
2 years ago
The first 2 terms of an ap is -2 and 3 how many terms are needed for the sum to be equal to 306 ​
Zepler [3.9K]

Answer:

306

Step-by-step explanation:

-2 + 3 = 1

so really it would take 306 times to get to this

6 0
3 years ago
use the guide to construct a two column proof proving △aec≅△deb, given that ca is parallel to db and e is the midpoint of ad. gi
MrMuchimi

By using the AAA congruence property of Triangles, △aec≅△deb is proved

It is given two triangles, Δaec and Δdeb, where e is the common point known as the midpoint of ad

Also, it is given that,

ca ║db

We need to prove that, △aec≅△deb

Then we'll use AAA congruence property of Triangles to prove the situation

As ca ║db

then, ∠cae = ∠ebd  (Alternate angles)

∠ace = ∠edb (Alternate angles)

and ∠aec = ∠deb (common angles)

Thus, by AAA congruence property, △aec≅△deb

Hence, proved

To learn more about, congruence property, here

brainly.com/question/2039214

#SPJ4

5 0
1 year ago
The sum of x and 15 please help
Anna007 [38]

Answer:

the sum of x and 15 is -16 because it is a straight line which means the straight line is a function.

4 0
3 years ago
One school purchased 16 gallons of blue paint to decorate several of its classrooms. If
Elodia [21]

Answer: zero

Explanation: if one classroom on its own needed 17 gallons of paint and they only purchased 16,-- which is less than needed for one classroom- how would there be enough for any other classroom?

4 0
3 years ago
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