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Evaluate the following expression for: x= -2, y=4, z=-3 4(2x+y)-2y+z

otez555 [7]

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$\blue\textsf{\textbf{\underline{\underline{Question:-}}}}$

Evaluate the expression 4(2x+y)-2y+z for x=-2, y=4 and z=-3

$\blue\textsf{\textbf{\underline{\underline{Answer and How to solve:-}}}}$

Before inserting the values of the variables, I recommend writing the equation in its simplest form.

First, use the distributive property and distribute 4:-

8x+4y-2y+z

Simplifying,

8x+2y+z

Now that the expression is in its simplest form, we can substitute the variables and simplify the expression.

First, write -2 in lieu of x:-

8(-2)+2y+z

-16+2y+z

Now, write 4 in lieu of y:-

-16+2(4)+z

-16+8+z

-8+z

Final step:-

write -3 in lieu of z:-

-8+(-3)

-8-3

-11

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7 0

1 year ago

a tennis ball is served from a height of 8 feet and just clears the net that is three feet high. The server is 40 feet from the

emmasim [6.3K]

Answer:

24

Step-by-step explanation:

7 0

2 years ago

There were 7 inches of rain in 24 hours. What is the average amount of rain per hour

Mademuasel [1]

Answer:

7 /24 inch per hour

Step-by-step explanation:

To find the average amount of rain, take the total amount of rain and divide by the time

7 inches / 24 hours

7 /24 inch per hour

7 0

2 years ago

A random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6. A random sample of 17 su

Sladkaya [172]

Answer:

We conclude that there is no difference in potential mean sales per market in Region 1 and 2.

Step-by-step explanation:

We are given that a random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6.

A random sample of 17 supermarkets from Region 2 had a mean sales of 78.3 with a standard deviation of 8.5.

Let $\mu_1$ = mean sales per market in Region 1.

$\mu_2$ = mean sales per market in Region 2.

So, Null Hypothesis, $H_0$ : $\mu_1-\mu_2$ = 0 {means that there is no difference in potential mean sales per market in Region 1 and 2}

Alternate Hypothesis, $H_A$ : > $\mu_1-\mu_2\neq$ 0 {means that there is a difference in potential mean sales per market in Region 1 and 2}

The test statistics that will be used here is Two-sample t-test statistics because we don't know about population standard deviations;

T.S. = $\frac{(\bar X_1 -\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+ {\frac{1}{n_2}}} }$ ~ $t__n_1_+_n_2_-_2$

where, $\bar X_1$ = sample mean sales in Region 1 = 84

$\bar X_2$ = sample mean sales in Region 2 = 78.3

$s_1$ = sample standard deviation of sales in Region 1 = 6.6

$s_2$ = sample standard deviation of sales in Region 2 = 8.5

$n_1$ = sample of supermarkets from Region 1 = 12

$n_2$ = sample of supermarkets from Region 2 = 17

Also, $s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }$ = $s_p=\sqrt{\frac{(12-1)\times 6.6^{2}+(17-1)\times 8.5^{2} }{12+17-2} }$ = 7.782

So, the test statistics = $\frac{(84-78.3)-(0)}{7.782 \times \sqrt{\frac{1}{12}+ {\frac{1}{17}}} }$ ~ $t_2_7$

= 1.943

The value of t-test statistics is 1.943.

Now, at a 0.02 level of significance, the t table gives a critical value of -2.472 and 2.473 at 27 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that there is no difference in potential mean sales per market in Region 1 and 2.

6 0

2 years ago

10. if ABC is equilaterteral, solve for x

djyliett [7]

Answer:

13

Step-by-step explanation:

If ABC is equilaterteral then all the angles must be equal and 60°

8x - 44 = 60 add 44 to both sides

8x = 104 divide both sides by 8

x = 13

8 0

3 years ago