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Licemer1 [7]
3 years ago
12

Help! Might have to zoom in

Mathematics
1 answer:
OlgaM077 [116]3 years ago
6 0
From the picture, I can make out two points: (0, 1) and (3, -1).
We plug into the slope formula:
\frac{y_2-y_1}{x_2-x_1} = \frac{-1-1}{3-0}=\boxed{-\frac{2}{3}}
and we have our answer.
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Fourteen students got a B on the last quiz. This represents 2/5 of the class. How many students are in the class?
Elena-2011 [213]
3/5 of the class is left
5 0
3 years ago
Read 2 more answers
Is 0.4 less than 0.12?
devlian [24]
No, .4 is larger then .12
4 0
4 years ago
Read 2 more answers
10x + 2 y = 24 <br>-5 x + y = -18​
wlad13 [49]

Answer:

(3,-3)

Step-by-step explanation:

First you divide 2 out of the first equation and it turns into 5x+y=12.

Then you write one on top of the other so you can add them. It looks like:

5x + y = 12

-5x + y = -18

Then you add them together and the 5x's cancel each other out and you are left with 2y = -6

So then you divide both sides by 2 and get y = -3

Then you plug -3 into the second equation because it is simpler and get -5x - 3 = -18

So then you add three to both sides and get -5x = -15

And finally you divide both sides by -5 and get x=3

6 0
4 years ago
Express the product of 2x squared plus 6x -8 and x+3 in standard form
NeTakaya

ANSWER

The standard form is:

2 {x}^{3}  + 12 {x}^{2}   + 10x - 24

EXPLANATION

The given product is

(2 {x}^{2}  + 6x - 8)(x + 3)

We expand using the distributive property to get:

x(2 {x}^{2}  + 6x - 8) + 3(2 {x}^{2}  + 6x - 8)

Expand the parenthesis;

2 {x}^{3}  + 6 {x}^{2}  - 8x + 6 {x}^{2}  + 18x - 24

This simplifies to

2 {x}^{3}  + 12 {x}^{2}   + 10x -24

Standard form is when the polynomial is arranged in decreasing powers of x.

8 0
4 years ago
Solve the following question​
Sedbober [7]
Answer:
81
Explanation:
[(2^2) (3^4) (12^3)]/[(2^5) (6^3)]
Whenever you have a number that can be separated into parts you can and give the same exponent:
[(2^2) (3^4) (2^3x2^3x3^3)]/[(2^5)(2^3x3^3)]
Whenever you multiply two terms with the same base, you can add the exponents:
=[(2^8)(3^7)]/[(2^8)(3^3)]
Take both 2^8’s out
=(3^7)/(3^3)
Whenever you have two exponents with the same base divided you just subtract the exponents:
=3^4
=81
The answer is 81
5 0
3 years ago
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