Given a Venn diagram showing the number of students that like blue uniform only as 32, the number of students that like gold uniform only as 25, the number of students that like blue and gold uniforms as 12 and the number of students that like neither blue nor gold uniform as 6.
Thus, the total number of students interviewed is 75.
Recall that relative frequency of an event is the outcome of the event divided by the total possible outcome of the experiment.
From the relative frequency table, a represent the relative frequency of the students that like gold but not blue.
From the Venn, diagram, the number of students that like gold uniform only as 25, thus the relative frequency of the students that like gold but not blue is given by

Therefore,
a = 33% to the nearest percent.
Similarly, from the relative frequency table, b represent the relative frequency of the students that like blue but not gold.
From
the Venn, diagram, the number of students that like blue uniform only
as 32, thus the relative frequency of the students that like gold but
not blue is given by

Therefore,
b = 43% to the nearest percent.
Answer:
A.
Step-by-step explanation:
If we assume that the population of the town is proportional to the random people selected to take the survey, then we can say that the answer is A, People at least 50 years old are the largest age group in town. Since the survey is random and the percentage of the 50-year old population group is higher when individually compared to the other groups, we can assume that the town's population consists of a high number of people who are 50-years old or older.
And although it is not a given answer choice, it would actually make more sense to say that out of the number of people that took the survey, those who were 50 years old or older consisted of the largest age group.
Answer:
x=120, y=160. and is that u in ur pfp
Step-by-step explanation:
780 as a percentage of 1.5
=

=52,000 percent of 1.5
5.9 × 10^24 = 5,900,000,000,000,000,000,000,000 minus
13,000,000,000,000,000,000,000 equals
5,887,000,000,000,000,000,000,000 kg
which is the amount greater that Earth's mass is. you could write this problem as
5.9 × 10^24 - 13 × 10^21 = 5.887 × 10^21