<h3>
Answer:</h3>
c) 7π cm
<h3>
Step-by-step explanation:</h3>
The length of an arc (s) is related to its central angle (θ) and the radius of the circle (r) by ...
... s = rθ . . . . . . . . . θ in radians
Here, the central angle measures are given in "grads". There are 400 grads in a circle, so 200 grads in π radians. To convert grads to radians, we multiply the number of grads by π/(200g).
Then the lengths of the arcs are ...
... arc AB = (20 cm)·(50g·(π/(200g))) = 5π cm
... arc BC = (10 cm)·(40g·(π/(200g))) = 2π cm
E = arc AB + arc BC = 5π cm + 2π cm = 7π cm
Answer:
2/1 or in better numbers 2
Step-by-step explanation:
Answer:
-10n - 12.5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Distributive Property
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Terms/Coefficients/Degrees
Step-by-step explanation:
<u>Step 1: Define</u>
-2.5(-3 + 4n + 8)
<u>Step 2: Simplify</u>
- Distribute -2.5: 7.5 - 10n - 20
- Combine like terms: -10n - 12.5
<h2>
Answer:</h2>
The raduis of the circle is given to Id.p. The raduis is 8.5 m. Calculate the lower bonds and the upper bonds:
<h2>
Explanation:</h2><h2>
</h2>
Hello! Remember you have to write complete questions in order to get good and exact answers. This question is incomplete but I'm going to help you assuming some things:
- The small rectangle is built up by the x and y-axis and the point
- The large rectangle is built up by the x and y-axis and the point that follows the rule:
For the small rectangle, the vertices are:
Therefore, if 
lies on the small rectangle, for the large rectangle we have:
In conclusion:
If point 
lies on the small rectangle, then 
lies on the large rectangle.
