Help solve for x. round to the nearest tenth
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we have been given that in ΔFGH, the measure of ∠H=90°, GF = 53, HG = 28, and FH = 45. We are asked to find the ratio that represents the sine of ∠G.
First of all, we will draw a right triangle using our given information.
We know that sine relates opposite side of right triangle with hypotenuse.
We can see from the attachment that opposite side to angle G is FH and hypotenuse is GF.
Therefore, the ratio represents the sine of ∠G.
