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Marta_Voda [28]
3 years ago
13

Cosby uses a weighted-average process-costing system. All materials are added at the beginning of the process; conversion costs

are incurred evenly throughout production. The company finished 40,000 units during the period and had 15,000 units in progress at year-end, the latter at the 40% stage of completion. Total material costs amounted to $220,000; conversion costs were $414,000. The cost of the ending work in process is: A. $54,000. B. $78,000. C. $114,000.D. $195,000. E. some other amount.
Business
1 answer:
Vlada [557]3 years ago
8 0

Answer:

C. $114,000

Explanation:

The material costs are added at the beginning of the process.

Total Material Cost = $220,000

\therefore Material cost per unit = $220,000 / (40,000+15,000) = $4

\therefore Material cost of ending work in process = 15,000 units * $4 = $60,000.

Conversion costs are incurred evenly throughout the process.

Total Conversion Costs = $414,000

Total units for which conversion cost has been incurred = 40,000 + (15,000 * 40%) = 46,000 units

\therefore Conversion cost per unit = $414,000 / 46,000 units = $9.

\therefore Conversion cost of ending work in process = 6,000 units * $9 = $54,000.

Thus, Total cost of ending work in process = $60,000 + $54,000 = $114,000.

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Answer:

$16,950

Explanation:

The computation of the shrinkage that occurred during the month is shown below:

Balance inventory = Beginning Inventory + Inventory purchased - Inventory sold

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Now the shrinkage inventory is

= Balance inventory - Physical count of inventory shows

= $544,950 - $528,000

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How gross profit or loss is computed​
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Illinois law requires that a pre-printed offer to purchase that is intended to become a binding contract have which of the follo
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3 years ago
A bank has $650,000 in assets to allocate among investments in bonds, home mortgages, car loans, and personal loans. Bonds are e
frosja888 [35]

Answer:

using solver, the optimal solution is:

$325,000 invested in bonds

$162,500.01 invested in mortgages

$162,499.99 invested in personal loans

maximum profit = $66,625

Explanation:

profit maximization equation:

0.1b + 0.085m + 0.095c + 0.125p

where:

b = money invested in bonds

m = money invested in mortgage loans

c = money invested in car loans

p = money invested in personal loans

constraints:

b + m + c + p ≤ 650,000

p ≤ 0.25 x 650,000 ⇒ p ≤ 162,500

m ˃ p

b ˃ p

using solver, the optimal solution is:

$325,000 invested in bonds

$162,500.01 invested in mortgages

$162,499.99 invested in personal loans

maximum profit = $66,625

actually solver gave me the following solution:

$325,000 invested in bonds

$162,500 invested in mortgages

$162,500 invested in personal loans

maximum profit = $66,625

since mortgage loans must be larger than personal loans, I added 1¢ to mortgage loans and subtracted 1¢ from personal loans

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