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sveticcg [70]
4 years ago
5

Help ASAP!!!! 1. Solve for x. Round to the nearest hundredth if necessary.

Mathematics
2 answers:
Effectus [21]4 years ago
8 0

Answer:

x ≈ 34.28

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan29° = \frac{opposite}{adjacent} = \frac{19}{x} ( multiply both sides by x )

x × tan29° = 19 ( divide both sides by tan29° )

x = \frac{19}{tan29} ≈ 34.28 ( to the nearest hundredth )

bagirrra123 [75]4 years ago
6 0

Answer:

The answer is option B

<h2>34.28</h2>

Step-by-step explanation:

To solve for x we use tan

tan ∅ = opposite / adjacent

From the question

The adjacent is x

The opposite is 19

So we have

tan 29 = 19/ x

x = 19/ tan 29

x = 34.276

<h3>x = 34.28 to the nearest hundredth</h3>

Hope this helps

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divide

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----------------    yields   1/8 = r^3      take the cube root  or each side

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an = a1r^(n-1)

an = a1 (1/2)^ (n-1)

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divide by 1/2

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an = -96 (1/2)^ (n-1)


the sum

Sn = a1[(r^n - 1/(r - 1)]

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4 years ago
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From the sum of a2−2ab+b2 and 2a2+2ab+b2 subtract the sum of a2−b2 and a2+ab+3b2
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Answer:

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Step-by-step explanation:

We need to find the sum of a^2-2ab+b^2 and 2a^2+2ab+b^2 first.

Adding a^2-2ab+b^2 + 2a^2+2ab+b^2

Combining like terms, we get

a^2+2a^2=3a^2

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b^2+b^2=2b^2

Therefore,

a^2-2ab+b^2 +2a^2+2ab+b^2=3a^2+2b^2.

Now, we need to find the sum of a^2-b^2 \ \ and \ \ a^2+ab+3b^2..

Adding a^2−b^2+a^2+ab+3b^2.

Combining like terms, we get

a^2+a^2=2a^2

-b^2+3b^2=2b^2.

Therefore,

a^2−b^2+a^2+ab+3b^2=2a^2+ab+2b^2.

Now, subtracting

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Distributing minus sign over second parenthesis, we get

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Combining like terms,

3a^2-2a^2=a^2

2b^2-2b^2=0

Therefore,

3a^2+2b^2-2a^2-ab-2b^2=a^2-ab.

Therefore, the difference of the sum of a^2-2ab+b^2 + 2a^2+2ab+b^2 and a^2-b^2+a^2+ab+3b^2. is a^2-ab.

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