<span>5 + 2i–4i + 15i12
2+ square root of 6</span>
Answer:
<h2>
![{x}^{2} + 9x - 16](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%209x%20-%2016)
</h2>
Step-by-step explanation:
![4 {x}^{2} + 8x - 7 - (3 {x}^{2} - x + 9)](https://tex.z-dn.net/?f=4%20%7Bx%7D%5E%7B2%7D%20%20%2B%208x%20-%207%20-%20%283%20%7Bx%7D%5E%7B2%7D%20%20-%20x%20%2B%209%29)
When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression:
![4 {x}^{2} + 8x - 7 - 3 {x}^{2} + x - 9](https://tex.z-dn.net/?f=4%20%7Bx%7D%5E%7B2%7D%20%20%2B%208x%20-%207%20-%203%20%7Bx%7D%5E%7B2%7D%20%20%2B%20x%20-%209)
Collect like terms
![4 {x}^{2} - 3 {x}^{2} + 8x + x - 7 - 9](https://tex.z-dn.net/?f=4%20%7Bx%7D%5E%7B2%7D%20%20-%203%20%7Bx%7D%5E%7B2%7D%20%20%2B%208x%20%2B%20x%20-%207%20-%209)
![{x}^{2} + 9x - 7 - 9](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%209x%20-%207%20-%209)
Calculate
![{x}^{2} + 9x - 16](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%209x%20-%2016)
Hope this helps...
Good luck on your assignment...
Answer:
D is the answer of the question
Yeah I'm not sure but I think it's 6