P(0,0) and Q(2a , 0)
Midpoint PQ
x = (x1 + x2)/2 and y = (y1 = y2)/2
Midpoint:
x = (2a +0)/2
= 2a / 2
= a
y = (0+ 0)/2
= 0/ 2
= 0
So midpoint PQ (a , 0)
Answer is the 1st option
(a, 0)
we know the diameter of the circle is 54, so the radius of it is half that or 27.
![\textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=27 \end{cases}\implies A=\pi (27)^2\implies \stackrel{using~\pi =3.14}{A=2289.06~mi^2}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D27%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%20%2827%29%5E2%5Cimplies%20%5Cstackrel%7Busing~%5Cpi%20%3D3.14%7D%7BA%3D2289.06~mi%5E2%7D)
Answer:
40 cm^2
Step-by-step explanation:
The area of the polygon is comprised of two triangles, each of which can be broken down into two right triangles for a total of four right triangles when split vertically.
The formula for the area of a triangle is: A = 1/2 * base * height.
The base for both triangles is 8 cm, and the height for both triangles is given on the right (6 cm for the top triangle and 4 cm for the bottom triangle).
The area of the top triangle will be:
A = 1/2 * 8 * 6
A = 4 * 6
A = 24
The area of the bottom triangle will be:
A = 1/2 * 8 * 4
A = 4 * 4
A = 16
Adding the values of the two areas, we get a total area of 40 cm^2.