Answer:
Step-by-step explanation:
r(t) = (7 cost + 7t sin t)i + (7 sin t - 7t cos t)j







Using eq (1) and (2)

Answer:
The percent error based on the average measurements is 0.8%.
Step-by-step explanation:
The standard equation for percent error is [(original - actual)/original} x 100. The original amount is 100 degrees celcius. Your average measurement can be found by adding the three temperatures together and dividing by the number of temperatures collected: 98.5 + 99.3 + 99.8 = 297.63/3 = 99.2. When we place our numbers into the equation and solve, we get: (100 - 99.2)/100 = 0.008 x 100 (to get our percentage) = 0.8%.
Answer:
327 children and 318 adults
Step-by-step explanation:
The x be the amount of children and y be the amount of adults that were at the swimming pool. We can use this to set up a system of equations:
x+y=645
1.75x+2.50y=1367.25
Move y to the other side in the first equation to isolate x and solve the system using substitution:
x=645-y
1.75(645-y)+2.50y=1367.25
Distribute
1128.75-1.75y+2.50y=1367.25
1128.75+0.75y=1367.25
Subtract 1128.75 from both sides
0.75y=238.5
Divide both sides by 0.75
y=318
x=645-y
x=645-318
x=327
327 children and 318 adults swam at the pool that day
no it's 22 :D...............
Answer:
No solution
Step-by-step explanation: