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3 years ago

Write this as a power of 2. ex ( 2^n) requires knowledge of negative exponents

Mathematics

1 answer:

Snowcat [4.5K]3 years ago

7 0

Answer:

Step-by-step explanation:

$\frac{32}{ \sqrt[8]{16} } \\$

Simplify

$\frac{32}{1.414213562} \\ \\ = 22.627417$

Method 2 :

By rationalizing the denominator

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8. Aimi decided to spend her money and save some in the ratio of 3:2. If her total money is RM

Bogdan [553]

Step-by-step explanation:

2/5×7500

2×1500

3000

RM=3000

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3 years ago

Tyrone opens a savings account by depositing $75 in August. He increases each of the next monthly deposits by $10. Which of the

RSB [31]

Answer:

Answer is C

Step-by-step explanation:

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3 years ago

Marcela is registering for her college classes, which cost $105 per unit. How many units can she take to have a maximum cost of

OverLord2011 [107]

Answer:

Marcela can take up to 13 units.

Step-by-step explanation:

In order to find the number of units that Marcela can take for her college classes, we can set up an inequality and solve for the variable. Since each unit costs $105, we can say that 105u ≤ 1365 where u = the number of units. The number of units multiplied by the cost per unit, must be less than or equal to $1,365. In order to solve for 'u', we can use inverse (opposite) operations and get rid of the coefficient by dividing both sides of the inequality by 105. 1365÷105 = 13. So, the number of units that Marcela can take must be less than or equal to 13 units.

6 0

3 years ago

Read 2 more answers

Which expression is equivalent to<br> 1/3/?

Rzqust [24]

Answer:

2\5,3\7,4\9,5\11

Thats the answer

3 0

3 years ago

The circular stream of water from a faucet is observed to taper from a diameter of 20 mm to 10 mm in a distance of 50 cm. Determ

steposvetlana [31]

Solution:

From Bernoulli equation

$\frac{1}{2}$ ρ $V_{1}^{2}$ + ρgh = $\frac{1}{2}$ ρ $V_{2}^{2}$ , where ρ is density of water, h – height difference and $V_{1}$ and $V_{2}$ are the velocities in upper and lower cross sections correspondingly. We take into account that the pressure in both cross-sections is the same and equal to the atmospheric one.

From the continuity and assuming water incompressible:

$\pi r_{1}^{2}$ $V_{1}$ = $\pi r_{2}^{2}$ $V_{2}$ , where $A_{1}$ and $A_{2}$ are the corresponding cross-sections. As the lower diameter is twice as low as the upper one, we can conclude that $V_{1} = \frac{V_{2}}{4}$

Inserting it back into Bernoulli equations produces:

$V_{1} = \sqrt{\frac{2}{15}gh} = 0.26m/s$ and the flow rate is

$\pi r_{1}^{2}V_{1} = \pi r_{2}^{2}V_{2} = 8.10^{-5} \frac{m^{3} }{s}$

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3 years ago