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Ad libitum [116K]
3 years ago
5

If f(x)=2x+7 and g(x)=11x-4, find (f+g)x.

Mathematics
1 answer:
klemol [59]3 years ago
7 0

Answer:

(f+g)(x) = 13x + 3

Step-by-step explanation:

Rewrite  f(x)=2x+7 and g(x)=11x-4 in columns, as follows:

f(x)=2x+7

+g(x)=11x-4

----------------

Now add each column separately.

f(x)+g(x) = (f+g)(x) ("the sum of functions f and g")

2x + 11x = 13x, and, finally, 7-4 = 3.


Therefore,

 f(x)=2x+7

+g(x)=11x-4

----------------

(f+g)(x) = 13x + 3

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<h2>Answers:</h2>

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  1. Answer : x =  \frac{-3}{2}⁻y + 16

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  • Solving for x on question - 5x - 4y = -81 |
  1. Answer : x =  \frac{4}{5}y + \frac{-81}{5}

  • Solving for y on question - 5x - 4y = -81 |
  1. Answer : y =  \frac{-5}{4}x + \frac{81}{4}
<h2>Step-by-step explanation:</h2>

<em>(Solving for x on question - 2x + 3y = 32)</em>

2x + 3y = 32

Step 1: Add -3y to both sides.

2x + 3y + −3y = 32 + −3y

2x = −3y + 32

Step 2: Divide both sides by 2.

\frac{2x}{2}  = \frac{-3y+32}{2}

<u>x =  </u>\frac{-3}{2}<u>⁻y + 16</u><u>                                                                                                                 </u>

<em>(Solving for y on question - 2x + 3y = 32)</em>

2x + 3y = 32

Step 1: Add -2x to both sides.

2x + 3y + −2x = 32+ −2x

3y = −2x + 32

Step 2: Divide both sides by 3.

\frac{3y}{3} =  \frac{-2x+32}{3}

<u>y = </u>\frac{-2}{3}<u>x + </u>\frac{32}{3}<u>                                                                                                           </u>

<em>(Solving for x on question - 5x - 4y = -81)</em>

5x − 4y = −81

Step 1: Add 4y to both sides.

5x − 4y + 4y = −81 + 4y

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Step 2: Divide both sides by 5.

\frac{5x}{5} =  \frac{4y-81}{5}

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<em>(Solving for y on question - 5x - 4y = -81 )</em>

5x − 4y = −81

Step 1: Add -5x to both sides.

5x − 4y + −5x = −81 + −5x

−4y = −5x − 81

Step 2: Divide both sides by -4.

\frac{-4y}{-4} = \frac{-5x-81}{-4}

y =  \frac{-5}{4}x + \frac{81}{4}

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