No, it is not a valid inference because her classmates do not make up a random sample of the students in the school.
Step-by-step explanation:
Although I cannot find any model or solver, we can proceed to model the optimization problem from the information given.
the problem is to maximize profit.
let desk be x
and chairs be y
400x+250y=P (maximize)
4x+3y<2000 (constraints)
according to restrictions y=2x
let us substitute y=2x in the constraints we have
4x+3(2x)<2000
4x+6x<2000
10x<2000
x<200
so with restriction, if the desk is 200 then chairs should be at least 2 times the desk
y=2x
y=200*2
y=400
we now have to substitute x=200 and y=400 in the expression for profit maximization we have
400x+250y=P (maximize)
80000+100000=P
180000=P
P=$180,000
the profit is $180,000
Answer:
I used the function normCdf(lower bound, upper bound, mean, standard deviation) on the graphing calculator to solve this.
- Lower bound = 1914.8
- Upper bound = 999999
- Mean = 1986.1
- Standard deviation = 27.2
Input in these values and it will result in:
normCdf(1914.8,9999999,1986.1,27.2) = 0.995621
So the probability that the value is greater than 1914.8 is about 99.5621%
<u><em>I'm not sure if this is correct </em></u><em>0_o</em>
Find x
5x-17 = 3x + 1
5x -3x = 17 + 1
2x = 18
2x/2 = 18/2
X = 9
Find the measure of FG
mFG = 5x - 17
mFG = 5(9) - 17
mFG = 45-17
mFG = 28
Answer:
Step-by-step explanation:
