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kotykmax [81]
3 years ago
9

. If α and β are the roots of

Mathematics
2 answers:
Lostsunrise [7]3 years ago
5 0

Answer:

18x^2+85x+18 = 0

Step-by-step explanation:

<u><em>Given Equation is </em></u>

=> 2x^2+7x-9=0

Comparing it with ax^2+bx+c = 0, we get

=> a = 2, b = 7 and c = -9

So,

Sum of roots = α+β = -\frac{b}{a}

α+β = -7/2

Product of roots = αβ = c/a

αβ = -9/2

<em>Now, Finding the equation whose roots are:</em>

α/β ,β/α

Sum of Roots = \frac{\alpha }{\beta } + \frac{\beta }{\alpha }

Sum of Roots = \frac{\alpha^2+\beta^2  }{\alpha \beta }

Sum of Roots = \frac{(\alpha+\beta )^2-2\alpha\beta   }{\alpha\beta  }

Sum of roots = (\frac{-7}{2} )^2-2(\frac{-9}{2} ) / \frac{-9}{2}

Sum of roots = \frac{49}{4} + 9 /\frac{-9}{2}

Sum of Roots = \frac{49+36}{4} / \frac{-9}{2}

Sum of roots = \frac{85}{4} * \frac{2}{-9}

Sum of roots = S = -\frac{85}{18}

Product of Roots = \frac{\alpha }{\beta } \frac{\beta }{\alpha }

Product of Roots = P = 1

<u><em>The Quadratic Equation is:</em></u>

=> x^2-Sx+P = 0

=> x^2 - (-\frac{85}{18} )x+1 = 0

=> x^2 + \frac{85}{18}x + 1 = 0

=> 18x^2+85x+18 = 0

This is the required quadratic equation.

dem82 [27]3 years ago
5 0

Answer:

α/β= -2/9      β/α=-4.5

Step-by-step explanation:

So we have quadratic equation  2x^2+7x-9=0

Lets fin the roots  using the equation's  discriminant:

D=b^2-4*a*c

a=2 (coef at x^2)   b=7(coef at x)  c=-9

D= 49+4*2*9=121

sqrt(D)=11

So x1= (-b+sqrt(D))/(2*a)

x1=(-7+11)/4=1   so   α=1

x2=(-7-11)/4=-4.5    so  β=-4.5

=>α/β= -2/9       => β/α=-4.5

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