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Mumz [18]
4 years ago
10

Please help me with this genetics problem, I will reward 91 Points. :((((

Biology
1 answer:
goblinko [34]4 years ago
5 0
<span>The genotype of the women is ttRR (taste blind and tongue rolling) whereas the genotype of man is Ttrr (Can taste PTC but no tongue rolling). The man is heterozygous for the taste as his mother was taste blind. 

The cross between them is shown below: 

Parents: Ttrr × ttRR Gametes: Tr, tr tR Progeny: Tr tr tR TtRr</span>
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dsp73

Answer:

Explanation:

Assuming the horizontally placed parent is the father, which is homo-zygous recessive  (a) for having sickle cell disease, i.e. he has the disorder.  This is where you have set up correctly.

On the other hand, a small adjustment is needed for the mother.  The mother (parent displayed vertically) is HOMO-zygous for <em>not</em> having the disease, hence she has alleles AA.  

Since both parents are homo-zygous, <em>all</em> offsprings are heterozygous for the disease.  Since sickle cell disease is recessive, it will need both copies of the mutated allele to have the disorder.  Therefore all their offsprings will not express the disorder (phenotype, no disease), but all are carriers (genotype Aa).

Note:

1. the punnett square you prepared is correct for the current genotype of the parents.  Well done.

2. Homo-zygous and hetero-zygous spell without hyphens.  Brainly will not let those correctly spelled words go through, so ended up putting in hyphens.

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3 years ago
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