50% or 0.5 is the probability that the offspring will have a cleft chin.
Explanation:
Data given:
Cleft chin = dominant, genotype CC
one parent, heterozygous so genotype, Cc
other parent = no cleft chin, genotype is cc (recessive)
probability of child with cleft chin =?
The cross between the given genotype will be shown in punnet square:
C c
c Cc cc
c Cc cc
The results obtained from the cross shows that 50% chances of the progeny having cleft chin.
The phenotype ratio: cleft chin: no cleft chin
1:1
the genotype ratio of the progeny
heterozygous dominant : recessive homozygous
1:1
As the question is incomplete i have added the complete question in ask for detail section.
Answer:
The correct options are:
A-C-E-G-I
A-C-E-I
A-C-G-I
Explanation:
Alternative splicing of RNA produces many mRNA strands from primary RNA transcript. When alternative splicing of RNA occurs, all the introns and some exons are removed. The removal of these exons produces different mRNA strands which are then translated into diffident kinds of proteins. Alternative splicing of RNA can highly increase the number of new produced proteins from same gene.
Answer:
pigs, badgers, bears, coatis, civets, hedgehogs, opossums, skunks, sloths, squirrels, raccoons, chipmunks, mice, and rats. The hominidae, including humans, chimpanzees, gorillas and orangutans are also omnivores.
Explanation:
Answer: Mutations can be good or bad.
Explanation: