In man, assume that spotted skin (S) is dominant over non-spotted skin (s) and that wooly hair (W) is dominant over non-wooly ha

Question

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In man, assume that spotted skin (S) is dominant over non-spotted skin (s) and that wooly hair (W) is dominant over non-wooly ha

ir (w). Cross a marriage between a heterozygous spotted, non-wooly man with a heterozygous wooly-haired, non-spotted woman. Give genotypic and phenotypic ratios of offspring.

Biology

1 answer:

Brut [27] · Answer 1 · 2021-11-22T16:48:14+03:00

Answer:

Total four genotypes and its frequency

SsWw – 4/16

ssWw- 4/16

Ssww - 4/16

ssww - 4/16

Phenotype –

SsWw – Heterozygous Spotted skin and heterozygous wooled hair

ssWw - Homozygous non-spotted skin and heterozygous wooled hair

Ssww - Heterozygous Spotted skin and Homozygous non -wooled hair

ssww - Homozygous non-spotted skin and Homozygous non -wooled hair

Explanation:

Given -

Allele for spotted skin is "S"

Allele for non-spotted skin is "s"

Allele for Wooly hair is "W"

Allele for non-wooly hair is "w"

Allele "S" is dominant over "s"

And Allele "W" is dominant over "w"

Cross is carried out between heterozygous spotted, non-wooly man and heterozygous wooly-haired, non-spotted woman

Genotype of heterozygous spotted, non-wooly man - Ssww

Genotype of heterozygous wooly-haired, non-spotted woman - ssWw

Ssww * ssWw

Sw Sw sw sw

sW SsWw SsWw ssWw ssWw

sw Ssww Ssww ssww ssww