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Oksi-84 [34.3K]
3 years ago
5

How do you solve the equations: -(1+4m)-6m=-81 and 238=-5(6v-7)-7

Mathematics
2 answers:
Murljashka [212]3 years ago
4 0
-(1+4m)-6m=-81
 -1-4m-6m=-81
-1-10m=-81
+1          +1
-10m=-80
---------------
-10
m=8

--------------------
238=-5(6v-7)-7
238=-30v+35-7
238=-30v+28
-28            -28
210=-30v
---------------
-30
v=7
irina [24]3 years ago
3 0
To solve an equation, we need to isolate the variable and simplify out other terms. In these equations, we will use the distributive property.

-(1+4m)-6m=-81     We start with our equation.
-1-4m-6m=-81     We distribute our "-."
-1-10m=-81     We combine our like-terms.
+1           +1
-10m=-80     We add1 to both sides (to isolate the variable).
/-10    /-10
m=8     We divide by -10 on both sides (to isolate the variable).

With the math above, we know that the solution to the first equation is that m=8. Now let's begin the second.

-5(6v-7)-7=238     We start with our equation.
-30v+35-7=238     We distribute our "-5."
-30v+28=238     We combine our like-terms.
        -28   -28
-30v=210     We subtract 28 from both sides (to isolate the variable).
/-30   /-30
v=-7     We divide by -30 on both sides (to isolate the variable).7

Using the math above, we can see that the solution to the second equation is v=-7.    
    
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The graph of y = 2(x - 3)² + 2 can be seen in the attached picture. This problem can be solved through the concept of parabola and transformation.

<h3>Further explanation</h3>

<u>The Problem:</u>

Which is the graph of y = 2(x - 3)² + 2?

<u>Question-1:</u>

How to make a graph y = 2 (x - 3) ² + 2 through the concept of a parabola.

<u>The Process:</u>

The equation of a parabola is given by \boxed{ \ y = a(x - h)^2 + k \ }.

Keep in mind the following points:

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From our case it can be concluded as follows:

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<u>Question-2:</u>

How to make the graph of y = 2(x - 3)² + 2 through the transformation.

<u>The Process:</u>

To plot the graph of y = 2(x - 3) ² + 2 we apply for the following transformation order:

Step-1: clearly, to obtain the graph of y = (x - 3)² we shift the graph of y = x² to the right 3 units.

Step-2: to obtain the graph of y = 2(x - 3)², we stretch the graph of y = (x - 3)²  by a factor of 2 (in other words, multiply each y-coordinate by 2).

Step-3: finally, to obtain the graph of y = 2(x - 3)² + 2 we shift the graph of y = 2(x - 3)² upward 3 units.

Thus the construction of the graph y = 2 (x - 3) ² + 2 is completed.

The graph of y = 2(x - 3) ² + 2 is drawn by the combination of shifting the graph of y = x² to the right 3 units and upward 2 units, and also stretch by a factor of 2. Between vertical shift and stretch steps, it is the same whatever steps are taken first.

- - - - - - - - - -

Notes

  • The transformation of graphs is changing the shape and location of a graph.  
  • There are four types of transformation geometry: translation (or shifting), reflection, rotation, and dilation (or stretching/shrinking).  
  • In this case, the transformation is shifting horizontally and vertically and also stretching vertically.

In general, given the graph of y = f(x) and v > 0, we obtain the graph of:  

  • \boxed{ \ y = f(x) + v \ } by shifting the graph of \boxed{ \ y = f(x) \ } upward v units.  
  • \boxed{ \ y = f(x) - v \ } by shifting the graph of \boxed{ \ y = f(x) \ } downward v units.  

That's the vertical shift, now the horizontal one. Given the graph of y = f(x) and h > 0, we obtain the graph of:  

  • \boxed{ \ y = f(x + h) \ } by shifting the graph of \boxed{ \ y = f(x) \ } to the left h units.  
  • \boxed{ \ y = f(x - h) \ } by shifting the graph of \boxed{ \ y = f(x) \ } to the right h units.

Hence, the combination of vertical and horizontal shifts is as follows:  

\boxed{ \ y = f(x \pm h) \pm v \ }  

The plus or minus sign follows the direction of the shift, i.e., up-down or left-right .

Notice the following definitions for stretch and shrink.

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  • In general, given the graph of \boxed{y = f(x)}, we obtain the graph of \boxed{y = f(cx)} by stretching \boxed{ \ 0 < c < 1 \ } or shrinking \boxed{ \ c > 1 \ } the graph of \boxed{y = f(x)} horizontally by a factor of c.
<h3>Learn more  </h3>
  1. What is the y-intercept of the quadratic function  f(x) = (x – 6)(x – 2)? brainly.com/question/1332667
  2. Transformations that change the graph of (f)x to the graph of g(x) brainly.com/question/2415963
  3. Which statement correctly describes the graph  brainly.com/question/10929552

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