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lesantik [10]
3 years ago
15

Select one of the factors of 5x2 + 7x + 2.

Mathematics
2 answers:
Dafna1 [17]3 years ago
6 0
5x² + 5x + 2x + 2
5x(x + 1) + 2(x + 1)

(5x + 2)(x + 1)
Anon25 [30]3 years ago
4 0
(5x + 2)(x + 1)

Above are the factors. You can get these by looking for numbers in the front that multiply to the first term and numbers in the back that multiply to the last term. Then FOIL to see if it works for the middle term. There is some trial and error to this. 
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((6x-8)-2x)-((12x-7)-(4x-5))
KengaRu [80]

Answer:

-12x + 4

Step-by-step explanation:

(6x - 8 - 2x) - (12x - 7) - (4x - 5)

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6 0
2 years ago
Select two choices that are true about the function f(x)=23x+14/x
WINSTONCH [101]

Answer:

There is an asymptote at x = 0

There is an asymptote at y = 23

Step-by-step explanation:

Given the function:

(23x+14)/x

Vertical asymptote is gotten by equating the denominator to zero

Since the denominator is x, hence the vertical asymptote is at x = 0. This shows that there is an asymptote at x = 0

Also for the horizontal asymptote, we will take the ratio of the coefficient of the variables in the numerator and denominator

Coefficient of  x at the numerator = 23

Coefficient of x at the denominator = 1

Ratio = 23/1 = 23

This means that there is an asymptote at y = 23

8 0
3 years ago
There are 15 students on a yearbook committee. 40% of the students are females. How many students on the committee are males?
Andrei [34K]

Answer:

9 students on the committee are males

Step-by-step explanation:

As per the statement:

There are 15 students on a yearbook committee.

⇒Total students on a yearbook committee = 15

⇒\text{Male students} +\text{Female students} = 15     ....[1]

It is given that:

40% of the students are females

⇒\text{Female students} = \frac{40}{100} \cdot 15 = 6

Substitute in [1] we have;

\text{Male students} + 6 = 15

Subtract 6 from both sides we have;

\text{Male students}= 9

Therefore, 9 students on the committee are males

8 0
4 years ago
Read 2 more answers
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