Answer:
2/35
Step-by-step explanation:
original equation:q+1/7=1/5
subtract both sides by 1/7
q=1/5-1/7
q=2/35
(give me brainly pls)
Answer: the awnser is b 22.2.
Step-by-step explanation: have a nice day
Answer:
Time required by Machine B to create a widget = 4 hours
Step-by-step explanation:
Time taken by Machine A (
) = 3 hours
Time taken by Machine B (
)= x hours
Time taken by both machines by working together = 12 hours
The time required to both machines by working together to finish a task is given by the formula = 
Put the values in above formula we get
⇒ T = 
⇒ 12 = 
⇒ 36 + 12 x = 3 x
⇒ x = - 4 hours
This is the time required by Machine B to create a widget.
Answer:
The numerical limits for a B grade is between 81 and 89.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

B: Scores below the top 13% and above the bottom 56%
Below the top 13%:
Below the 100-13 = 87th percentile. So below the value of X when Z has a pvalue of 0.87. So below X when Z = 1.127. So




Above the bottom 56:
Above the 56th percentile, so above the value of X when Z has a pvalue of 0.56. So above X when Z = 0.15. So




The numerical limits for a B grade is between 81 and 89.
When adding two together multiply:
log2 6 + log2 2 = log2(6*2) = log2 12
When you subtract 2 logs, divide:
So you have log2 12 / log2 8
Rewrite as log2 12/8
Simplify to get log2 3/2
The answer is C.