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Evgen [1.6K]
3 years ago
8

1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30=

Mathematics
1 answer:
Finger [1]3 years ago
7 0

Answer: 465

Step-by-step explanation: thx for the free points :)

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Solve q + 1/7 = 1/5. Express your answer in the simplest form.
o-na [289]

Answer:

2/35

Step-by-step explanation:

original equation:q+1/7=1/5

subtract both sides by 1/7

q=1/5-1/7

q=2/35

(give me brainly pls)

4 0
3 years ago
T<br>this is a 7.5 trig ratios solving missing sides assignment ​
Vsevolod [243]

Answer: the awnser is b 22.2.

Step-by-step explanation: have a nice day

4 0
3 years ago
Working alone and at a constant rate, Machine A takes 3 hours to create a widget. Machine B, working alone and at a constant rat
PilotLPTM [1.2K]

Answer:

Time required by Machine B to create a widget = 4 hours

Step-by-step explanation:

Time taken by Machine A ( T_{A} ) = 3 hours

Time taken by Machine B ( T_{B} )= x hours

Time taken by both machines by working together = 12 hours

The time required to both machines by  working together to finish a task is given by the formula = \frac{T_{A} {T_{B} } }{T_{A} + T_{B} }

Put the values in above formula we get

⇒ T =  \frac{3 x}{3 + x}

⇒ 12 =  \frac{3 x}{3 + x}

⇒ 36 + 12 x = 3 x

⇒ x = - 4 hours

This is the time required by Machine B to create a widget.

8 0
3 years ago
An art history professor assigns letter grades on a test according to the following scheme. A: Top 13%13% of scores B: Scores be
amm1812

Answer:

The numerical limits for a B grade is between 81 and 89.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 79.7, \sigma = 8.4

B: Scores below the top 13% and above the bottom 56%

Below the top 13%:

Below the 100-13 = 87th percentile. So below the value of X when Z has a pvalue of 0.87. So below X when Z = 1.127. So

Z = \frac{X - \mu}{\sigma}

1.127 = \frac{X - 79.7}{8.4}

X - 79.7 = 8.4*1.127

X = 89

Above the bottom 56:

Above the 56th percentile, so above the value of X when Z has a pvalue of 0.56. So above X when Z = 0.15. So

Z = \frac{X - \mu}{\sigma}

0.15 = \frac{X - 79.7}{8.4}

X - 79.7 = 8.4*0.15

X = 81

The numerical limits for a B grade is between 81 and 89.

3 0
3 years ago
Please help ASAP 30 pts + brainliest to right/best answer
Delicious77 [7]

When adding two together multiply:

log2 6 + log2 2 = log2(6*2) = log2 12

When you subtract 2 logs, divide:

So you have log2 12 / log2 8

Rewrite as log2 12/8

Simplify to get log2 3/2

The answer is C.

4 0
4 years ago
Read 2 more answers
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