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Umnica [9.8K]
3 years ago
15

Which expression is 444 times as large as the expression 34 -15

Mathematics
1 answer:
Yakvenalex [24]3 years ago
7 0

Answer:

c

Step-by-step explanation:

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56 apples

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Area model multiplication: 2x2 digits what to do forget how to do it
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Which vertex will result in the minimum value of the function T = x - 2y?
PilotLPTM [1.2K]

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the objective function, P, at each vertex ... Example: Find the maximum and minimum values of P=3x+2y subject to x + 4y ≤ 20 ... We can find the intersection of the two lines.

6 0
3 years ago
From the set {80, 19, 11}, use substitution to determine which value of x makes the equation true. 8x = 88 A. none of these B. 1
mel-nik [20]

Answer:

  C.  11

Step-by-step explanation:

Substituting, we have ...

  8{80, 19, 11} ?= 88

  {640, 152, 88} ?= 88

The value from the set that makes the equation true is x = 11.

_____

<em>Alternate methods of solution (other than substitution)</em>

It can be easier to make use of your knowledge of factoring:

  8x = 8·11

  x = 11

Or to make use of your knowledge of numbers (place value):

  8·10 = 80

so x will not be very different from 10.

3 0
3 years ago
PLEASE HELP ME!!!!!!!!!
vitfil [10]
<h2>1)</h2>

(x - 4) {}^{2}  - 28 = 8 \\ (x - 4) {}^{2}  = 8 + 28 \\ (x - 4) {}^{2}  = 36

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

\sqrt{(x - 4) {}^{2} }  =  ± \sqrt{36}  \\x - 4 = ±6 \\ x _{1}- 4 = 6 \:  \:  \:  \:  \:  \:  \: \:  \:  \:  x _{2}- 4 =  - 6 \\ x_{1} = 6 + 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2} =  - 6 + 4 \\ x_{1} = 10 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: \:  \: x_{2} =  - 2

<h2>2)</h2>

Well he started off correct to the point of completing the square.

(x - 3)  {}^{2}  = 16 \\ x - 3 = ±4 \\  \: x_{1}  - 3 = 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  - 3 =  - 4 \\ x_{1}  = 7 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  =  - 1

8 0
10 months ago
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