Given: Q = 7m + 3n, R = 11 - 2m, S = n + 5, and T = -m - 3n + 8. Simplify R - S + T

1 answer:

5 0

$Q=7m+3n\\R=11-2m\\S=n+5\\T=-m-3n+8\\\\R-S+T=(11-2m)-(n+5)+(-m-3n+8)\\\\=11-2m-n-5-m-3n+8\\\\=(-2m-m)+(-n-3n)+(11-5+8)\\\\=\boxed{-3m-4n+14}$

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Step-by-step explanation:

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Problems of normally distributed distributions are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

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