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3 years ago

The rate of change in the function Y = 2X +5 is the rate of change of the function represented in the table

Mathematics

1 answer:

Alex17521 [72]3 years ago

7 0

Answer:

The rate of change in the function Y = 2X +5 is <u>greater than</u> the rate of change of the function represented in the table

Step-by-step explanation:

The given function is

$y = 2x + 5$

For a linear function in the form y=mx +c, the rate of change is <em>m</em>.

The rate of change of this function is 2

We now determine the rate of change of the function represented in the table.

This is given by

$\frac{change \: in \: y}{ change \: in \: x}$

Using the corresponding values from the table, the rate of change is

$\frac{6 - 4}{5 - 3} = \frac{2}{2} = 1$

Therefore the rate of change in the function Y = 2X +5 is greater than the rate of change of the function represented in the table

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Answer:

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Step-by-step explanation:

$36-\left[100\div \:560-32\left(8\div \:4-1\right)\right]\\\\100\div \:560-32\left(8\div \:4-1\right)\\\\=100\div \:560-32\cdot \:1\\\\=\frac{100}{560}-32\cdot \:1\\\\=\frac{100}{560}-32\\\\=-\frac{891}{28}\\\\\\=36-\left(-\frac{891}{28}\right)\\\\36-\left(-\frac{891}{28}\right)\\\\=36+\frac{891}{28}\\\\\frac{36\cdot \:28}{28}+\frac{891}{28}\\\\\frac{36\cdot \:28+891}{28}\\\\=\frac{1899}{28}\\\\\\\frac{1899}{28}(1899\div28)=67\frac{23}{28}$

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