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3 years ago

Can you help with 5 math multiple question their easy

Mathematics

1 answer:

levacccp [35]3 years ago

4 0

1. yes because they go into it equally
2. 2 3 4 5 9 10
3. 3 5 9
4. 300 and 400 because 100 x 3 is 300 and 4 x 100 is 400
5. 9000 and 5000 because 9 x 1000 is 9000 and 5 x 1000 is 5000

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For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of

Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is $(-1)^{k+1}(\frac{1}{2^{k}})$ .

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as $(-1)^{k+1}(\frac{1}{2^{k}})$ .

where k is from 1 to 10.

By the given expression sequence will be $\frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......$

In this sequence first term "a" = $\frac{1}{2}$

and common ratio in each successive term to the previous term is 'r' = $\frac{\frac{(-1)}{4}}{\frac{1}{2} }$

r = $-\frac{1}{2}$

Since the sequence is infinite and the formula to calculate the sum is represented by

$S=\frac{a}{1-r}$ [Here r is less than 1]

$S=\frac{\frac{1}{2} }{1+\frac{1}{2}}$

$S=\frac{\frac{1}{2}}{\frac{3}{2} }$

S = $\frac{1}{3}$

Now we are sure that the sum of infinite terms is $\frac{1}{3}$ .

Therefore, sum of 10 terms will not exceed $\frac{1}{3}$

Now sum of first two terms = $\frac{1}{2}-\frac{1}{4}=\frac{1}{4}$

Now we are sure that sum of first 10 terms lie between $\frac{1}{4}$ and $\frac{1}{3}$

Since $\frac{1}{2}>\frac{1}{3}$

Therefore, Sum of first 10 terms will lie between $\frac{1}{4}$ and $\frac{1}{2}$ .

Option D will be the answer.

3 0

3 years ago

A car traveled 180 miles and used 6 gallons of gas. If the same car traveled 1,260 miles at the same rate, how many gallons of g

Luba_88 [7]

Answer:

180miles=6gallons

1260miles=?gallons

1260/180*6

=42 gallons

Step-by-step explanation:

6 0

2 years ago

18. Two planes left an airport at the same time. One flew north at a set speed and the other

Andre45 [30]

Answer: plane A = 333.33mph

Plane B = 500mph

Step-by-step explanation:

Given data:

Distance between the two planes = 2400miles.

Plane A flew North

Plane B flew south

Solution:

Let v represent plane A.

Let 2v represent plane B.

Distance between the two plane

v + 1.5* v = 3*v

7.5v = 2500miles

v = 333.33mph

Plane B has one and half times the speed of plane A

= 1.5 * 333.33

= 500mph

4 0

3 years ago

Why did I get this question wrong?

lord [1]

Step-by-step explanation:

∫₀³⁰ (r/V C₀ e^(-rt/V)) dt

If u = -rt/V, then du = -r/V dt.

∫ -C₀ e^u du

-C₀ ∫ e^u du

-C₀ e^u + C

-C₀ e^(-rt/V) + C

Evaluate between t=0 and t=30.

-C₀ e^(-30r/V) − -C₀ e^(-0r/V)

-C₀ e^(-30r/V) + C₀

C₀ (-e^(-30r/V) + 1)

I got the same answer. Try changing the lowercase v to an uppercase V.

4 0

3 years ago

Can someone answer #13, #15, and #16

Dominik [7]

#13: b
#14: c
#16: c

It is very easy, have a nice day :)

8 0

3 years ago

Read 2 more answers