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kolbaska11 [484]
3 years ago
11

If it were possible to eat a hamburger every minute of every day without stopping how many years would it take to eat a billion

hamburgers
Mathematics
1 answer:
Helga [31]3 years ago
8 0
I billion hamburgers would be eaten in 1 billion minutes, which would translate to 1903 years.
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3 pe cat este egal cu 8 pe cat
NemiM [27]
Se puede escribir esto en Inglés por favor?
6 0
3 years ago
PLEASE HELP I HAVE 10 MINUTES LEFT
Lena [83]

Answer:

Manufacturers has to produce 63 DVD/Blu-Ray players to achieve a minimum cost of $644

Step-by-step explanation:

The cost equation is given as:

C=0.04x^2-5x+800

This is a quadratic equation in general form, which is:

y=ax^2+bx+c

Matching, we can say:

a = 0.04

b = -5

c = 800

The minimum occurs at  x=-\frac{b}{2a}

and the minimum value would be to place that "x" value into the equation.

First, we find the minimum using values of a and b:

x=-\frac{b}{2a}=-\frac{-5}{2(0.04)}=\frac{5}{0.08}=62.5

Plugging this into original, we get:

C=0.04x^2-5x+800\\C=0.04(62.5)^2-5(62.5)+800\\C=643.75

Rounding off to nearest whole number, we can say:

Manufacturers has to produce 63 DVD/Blu-Ray players to achieve a minimum cost of $644

4 0
3 years ago
If you could help that would be awesome.
Nadusha1986 [10]

Answer:

2:1

Step-by-step explanation:

4 pencils : 2 pens

simplify...

2 pencils : 1 pen

2:1

Hope this is helpful.

6 0
2 years ago
(7x – 10) – (–6x – 8).
xeze [42]

Answer:

13x-2

Step-by-step explanation:

1) distribute the negative sign to each term in the second parentheses

(7x-10)-(-6x-8)

7x-10+6x+8

2) combine like terms

7x+6x= 13x

-10+8=-2

13x-2

Hope this helps!

4 0
2 years ago
If every student in a large Statistics class selects peanut M&M’s at random until they get a red candy, on average how many
kotykmax [81]

Question:

According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select peanut M&M's from an extra-large bag looking for a red candy.

If every student in a large Statistics class selects peanut M&M’s at random until they get a red candy, on average how many M&M’s will the students need to select? (Round your answer to two decimal places.).

Answer:

If every student in the large Statistics class selects peanut M&M’s at random until they get a red candy the expected value of the number of  M&M’s the students need to select is 8.33 M&M's.

Step-by-step explanation:

To solve the question, we note that the statistical data presents a geometric mean. That is the probability of success is of the form.

The amount of repeated Bernoulli trials required before n eventual success outcome or

The probability of having a given number of failures before the first success is recorded.

In geometric distribution, the probability of having an eventual successful outcome depends on the the completion of a certain number of attempts with each having the same probability of success.

If the probability of each of the preceding trials is p and the kth trial is the  first successful trial, then the probability of having k is given by

Pr(X=k) = (1-p)^{k-1}p  

The number of expected independent trials to arrive at the first success for a variable Xis 1/p where p is the expected success of each trial hence p is the probability for the red and the expected value of the number of trials is 1/p or where p = 12 % which is 0.12

1/p = 1/0.12 or 25/3 or 8.33.

4 0
3 years ago
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