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Ierofanga [76]
3 years ago
11

An electric company has to track on-time payments and late payments for each customer monthly. It is impossible for a customer t

o pay on-time and late each month. If the probability that a customer pays on-time each month is 0.55, and the probability that a customer pays late or on-time each month is 0.82, what is the probability that a customer pays late each month
Mathematics
1 answer:
OLga [1]3 years ago
8 0

Answer:

The  probability that a customer pays late each month is    P(B)  =  0.27

Step-by-step explanation:

Let     P( A ) be the probability that the customer pays on time and the value is  0.55

Let  P( B )  be the  probability that a customer pays late each month

So

  The probability that a customer pays late or on-time each month  is  P(A u B) and  the value is  0.82

The probability that a customer pays on-time and late each month is  P(A n B) and  the value is  zero ( 0 ) given that it is impossible

   Now The probability that a customer pays late or on-time each month  is mathematically represented as

      P(A u B)  =  P(A) +  P(B)  -   P(A n B)

=>     0.82  =  0.55 + P( B ) -   0

=>    P(B)  =  0.27

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the price of the cell phone is expected to increase by 165% in September 2015. The current price of a cell phone is $62.80. What
Sladkaya [172]

Answer:

$166.42.

Step-by-step explanation:

We have been given that the price of the cell phone is expected to increase by 165% in September 2015. The current price of a cell phone is $62.80.

The price of cell phone in September 2015 will be $62.80 plus 165% of $62.80.

\text{The predicted cost of a cell phone in September 2015}=\$62.80+(\frac{165}{100}*\$62.80)

\text{The predicted cost of a cell phone in September 2015}=\$62.80+(1.65*\$62.80)

\text{The predicted cost of a cell phone in September 2015}=\$62.80+\$103.62

\text{The predicted cost of a cell phone in September 2015}=\$166.42

Therefore, the predicted cost of a cell phone in September 2015 will be $166.42.

4 0
3 years ago
Find the first four terms for the arithmetic sequence given a1 = 6 and d = 5
DENIUS [597]

Answer:

6, 11, 16, 21

Step-by-step explanation:

To obtain the first 4 terms add the common difference 5 to the previous term, that is

a₁ = 6

a₂ = a₁ + 5 = 6 + 5 = 11

a₃ = a₂ + 5 = 11 + 5 = 16

a₄ = a₃ + 5 = 16 + 5 = 21

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3 years ago
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3 years ago
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Mason plans to use a strategy to find the product of 32 * 250. Write a strategy Mason could use to find the product.
Romashka [77]
I think Mason could use a calculator
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3 years ago
if a sequence is defined recursively by f(0)=4 and f(n+1)= -3f(n+1)=-3f(n)+1 for n≥0, then f(3) is equal to? DESPERATELY NEED HE
muminat

f(3) is equal to -101.

<u>Step-by-step explanation</u>:

  • The sequence is followed by f(0)=4
  • The given expression is f(n+1)= -3f(n)+1

Put n=0,

f(0+1)= -3f(0)+1

f(1)= -3(4)+1

f(1)= -12+1 = -11

Put n=1,

f(1+1)= -3f(1)+1

f(2)= -3(-11)+1

f(2)= 33+1 = 34

Put n=2,

f(2+1)= -3f(2)+1

f(3)= -3(34)+1

f(3)= -102+1

f(3)= -101

5 0
3 years ago
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